How to integrate this by parts?

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SUMMARY

The discussion focuses on integrating a specific expression involving the curl operator by parts. The integral in question is \int d^{3}y\, e^{ik(\hat{n}_{0}-\hat{n})\cdot\vec{y}}\left[ \nabla\times\nabla\times\hat{\epsilon}_{0} \right], with the goal of achieving a result proportional to \int d^{3}y\, e^{ik(\hat{n}_{0}-\hat{n})\cdot\vec{y}} \hat{n}\times\hat{n}\times\hat{\epsilon}_{0}. The discussion emphasizes the necessity of applying the product rule for differentiation and the definition of the curl operation to facilitate the integration process.

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THIS HOMEWORK PROBLEM WAS SUBMITTED TO THE WRONG FORUM, AND THERE IS NO TEMPLATE.
Hey guys,

So here's the issue I'm faced with. I need to integrate the following by parts (twice):

[itex]\int d^{3}y\, e^{ik(\hat{n}_{0}-\hat{n})\cdot\vec{y}}\left[ \nabla\times\nabla\times\hat{\epsilon}_{0} \right][/itex]

And I have absolutely no clue how to approach this. The result I'm meant to reach is proportional to

[itex]\int d^{3}y\, e^{ik(\hat{n}_{0}-\hat{n})\cdot\vec{y}} \hat{n}\times\hat{n}\times\hat{\epsilon}_{0}[/itex]

The hats denote unit vectors I believe.

I don't know how to integrate by parts an expression involving the curl operator...can someone help please?

Thanks!
 
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Integration by parts in the usual case works because of the product rule for differentiation:

$$ \frac{d}{dx} (f g) = \frac{df}{dx} g + f \frac{dg}{dx} .$$

In your case, you need to use some definition of the curl operation to show that

$$ \nabla \times (f \vec{A}) = \nabla f \times \vec{A} + f (\nabla \times \vec{A}).$$

You can then manipulate this in a way analogous to the usual integration by parts formula to find an appropriate generalization.
 

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