Graduate How to Solve This Differential Equation Analytically?

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SUMMARY

The discussion focuses on solving the differential equation $$\frac{2 y''}{y'} - \frac{y'}{y} = \frac{x'}{x}$$ analytically. Key hints provided include the transformations $$\frac{2y''}{y'}=2\log\left(y'\right)', \frac{y'}{y}=\log\left(y\right)',$$ and $$\frac{x'}{x}=\log\left(x\right)'.$$ These transformations simplify the equation, allowing for a clearer path to finding the solution. Santiago's hints are crucial for understanding the relationship between the derivatives and logarithmic functions involved in the equation.

PREREQUISITES
  • Understanding of differential equations and their components
  • Familiarity with logarithmic differentiation
  • Knowledge of the relationship between functions and their derivatives
  • Basic calculus skills, particularly in solving second-order differential equations
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  • Study the method of logarithmic differentiation in depth
  • Explore techniques for solving second-order differential equations
  • Learn about the applications of differential equations in modeling real-world phenomena
  • Investigate the use of transformation techniques in simplifying complex equations
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Mathematics students, educators, and professionals involved in analytical problem-solving, particularly those focusing on differential equations and their applications.

SantiagoCR
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TL;DR
calculate integral of a differential equation
Hello,

can someone help me to solve the following differential equation analitically:

$$\frac{2 y''}{y'} - \frac{y'}{y} = \frac{x'}{x}$$

where ##y = y(t)## and ##x = x(t)##

br

Santiago
 
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Hint: $$\frac{2y''}{y'}=2\log\left(y'\right)',\quad\frac{y'}{y}=\log\left(y\right)',\quad\frac{x'}{x}=\log\left(x\right)'$$
 
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renormalize said:
Hint: $$\frac{2y''}{y'}=2\log\left(y'\right)',\quad\frac{y'}{y}=\log\left(y\right)',\quad\frac{x'}{x}=\log\left(x\right)'$$
cool, thank you very much!
 
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