Magnitude of Potential Difference Between Two Points

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Homework Help Overview

The problem involves calculating the potential difference between two points in a circuit where a current of 1.2 A flows. The original poster expresses confusion about the relationship between current, resistance, and potential difference, referencing Ohm's law.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to calculate equivalent resistance in series and parallel configurations. Questions arise about how to combine resistors and the implications for potential difference across them.

Discussion Status

Some participants have offered guidance on finding equivalent resistance and understanding the circuit configuration. The discussion reflects a mix of interpretations and attempts to clarify concepts without reaching a definitive conclusion.

Contextual Notes

There are indications of confusion regarding the addition of resistors in different configurations, and the original poster mentions feeling lost during lectures. The presence of external resources is noted, suggesting a collaborative effort to enhance understanding.

anomalocaris
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potential diffeence.jpg
1. Homework Statement [/b]

So I found this problem online, and I really do not know how to go about solving it! My professor has done similar problems in class, but it's still a little confusing.

A current of 1.2 A flows from A to B. Therefore, the magnitude of the potential difference between points A and B is approximately

Homework Equations


I know Δv=IR and Ampere/Volt makes an Ω

The Attempt at a Solution



Well, the image attached already gives the answer, it should be 6.0 V. The current is given (1.2 A), so I'm guessing by the units that I must multiply something with Ω to get Volts. Should I add up the resistors?

Thank you!
 
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To do this problem, you are going to need to be able to "add" resistors in parallel and series. Need help with that?
 
anomalocaris said:
Well, the image attached already gives the answer, it should be 6.0 V. The current is given (1.2 A), so I'm guessing by the units that I must multiply something with Ω to get Volts. Should I add up the resistors?

Sure. Find the equivalent resistance between points A and B. Then see what potential drop occurs across it due to the given current value.
 
lewando said:
To do this problem, you are going to need to be able to "add" resistors in parallel and series. Need help with that?


Haha, lewando, yes please!

Would we consider the two 6Ω resistors parallel? And if so, the potential difference there is the same? We are getting to the point where I just smile and nod during the lecture even though I am completely lost!
 
lewando said:
Well then take a look at the following two websites:
http://www.allaboutcircuits.com/vol_1/chpt_5/1.html (for a definition of series/parallel)
http://en.wikipedia.org/wiki/Series_and_parallel_circuits (for how to combine them)

Give them a read and come back with any questions.

Thank you so much! I just had an epiphany and this is all way less complicated! Thank you to all who replied. And thank you so much, lewando. I wasn't taking the reciprocals of the resistances and so I was adding them incorrectly, but now it all makes much more sense. I ended up with an R_eq of 5Ω, which when multiplied by 1.2 A yields a potential difference of 6 V. Thank you so much!
 

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