How to Obtain a Magnification of -2 from a Convex Lens?

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To achieve a magnification of -2 using a convex lens, the object must be positioned correctly in relation to the lens's focal length. The discussion emphasizes that for an inverted image, the object must be placed at a distance of 3f/2 from the lens, making option C the correct choice. It is noted that placing the object between the focal point and the lens results in a virtual and erect image, which is not suitable for this scenario. The focal length of convex lenses is positive, and understanding the relationship between object distance and image distance is crucial for solving the problem. Overall, the key takeaway is that option C provides the necessary conditions for achieving the desired magnification.
Sylvia
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Homework Statement


You wish to obtain a magnification of -2 from a convex lens of focal length f. The only possible solution is to:

A) place a virtual object at a distance 2f/3 from the lens.
B) place a virtual object at a distance 5f/3 from the lens.
C) place a real object at a distance 3f/2 from the lens.
D) place a real object at a distance 2f/3 from the lens.
E) place a virtual object at a distance 3f/2 from the lens.

Homework Equations


(1/do) + (1/di) = (1/f)
m = -di/do
f is negative because it is a convex lens

The Attempt at a Solution


I'm not sure how to factor in focal length, I am unsure how to get the relationship between object distance and focal length
 
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Sylvia, you can attempt this quetion by eliminating approach.
Here's what you should consider,
First try by using real objects.
Note that for magnification of -2 you should have an inverted image.
We kniw for object between f and o , the image is virtual and erect hence,
Option D is ruled out.
Now considering option C
The objet will be between f and 2f
Hence image will be real and enlarged.
And also by putting magnification ( -v/u = -2) you can get your answer.
Hence option C seems correct to me.

If you want further solution letme know.
 
Sylvia said:

Homework Equations


(1/do) + (1/di) = (1/f)
m = -di/do
f is negative because it is a convex lens

The Attempt at a Solution


I'm not sure how to factor in focal length, I am unsure how to get the relationship between object distance and focal length

The focal length of convex lenses is positive.
You know how magnification defined. So you can express do in terms of di and substitute into the equation (1/do) + (1/di) = (1/f). Solve for do in terms of f.
 
Thank you both very much, I understand it now!
 
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