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How to obtain the Sellmeier equation based on a new material?

Problem Statement
I have synthesize a material used in optical transmission. I want to know its transmission constant beta and its higher derivative. So the first step is to use the Sellmeier equation to describe its refractive indices. And I have already tested a series of refractive indices value at different wavelengths. How to get ist Sellmeier equation ?
Relevant Equations
$$n=\sqrt{1+\frac{B_1}{\lambda^2-C_1}+\frac{B_2}{\lambda^2-C_2}+\frac{B_3}{\lambda^2-C_3}}$$
I have synthesize a material used in optical trasmission. I want to know its transmission constant beta and its higher derivative. so the first step is to use sellmeier equation to describe its refractive indices. and i have already test a series of refractive indices value in different wavelengh. how to get ist sellmeier equation ?
 
actually i cannot find the link you provide.
 

Charles Link

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It comes up on my computer.
 
maybe this link is forbidden in my place, anyway, thank you very much.
 

kuruman

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The equation in the link says
$$n^2(\lambda)=1+\frac{B_1\lambda^2}{\lambda^2-C_1}+\frac{B_2\lambda^2}{\lambda^2-C_2}+\frac{B_3\lambda^2}{\lambda^2-C_3}$$
 

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