How to Perform a Permutation with Multiple Cycles

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SUMMARY

The discussion focuses on performing permutations with multiple cycles, specifically the expression (1 2) (1 4 5) (2 3 4) (2 5) resulting in (1 4) (3 5). The user seeks clarification on how to derive the final result through explicit mapping of each element. The solution involves writing out the mappings for each cycle and composing them to determine the final permutation outcome.

PREREQUISITES
  • Understanding of permutation notation and cycle representation
  • Familiarity with mapping elements in permutations
  • Knowledge of composition of functions
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the concept of permutation cycles in group theory
  • Learn how to compose multiple permutations effectively
  • Explore examples of cycle notation and their mappings
  • Practice problems involving permutations to reinforce understanding
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Students studying abstract algebra, mathematicians interested in group theory, and anyone looking to deepen their understanding of permutations and cycle notation.

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Homework Statement



(1 2) (1 4 5) (2 3 4) (2 5)= (1 4) (3 5)

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The Attempt at a Solution



Can someone explain to me how to do this permutation? I know it's the easiest thing to do but i just went blank! how did my professor get (1 4) (3 5)?
 
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start by writing out each step explicitly

eg for the permutation p = (25) you have
p(1) = 1
p(2) = 5
p(3) = 3
p(4) = 4
p(5) = 2

so this gives p as the following map
1 2 3 4 5
1 5 3 4 2

then similar for the next permutations, then either stack the maps or cualcte where each element ends up to get the effect of composition of several permutations and you should be able to read off the final result
 

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