How to Prove that AB=2BC without using any of the given angles?

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SUMMARY

The discussion centers on proving that in parallelogram ABCD, the relationship AB = 2BC holds true under the conditions that angle DAE equals angle EAB and angle CBE equals angle EBA. Key insights include establishing angle AEB as 90 degrees, which aids in labeling the interior angles of the figure. By defining angles a, b, c, and d, and recognizing the congruence of triangles ADE and BEC, the conclusion that AB = 2BC is reached definitively.

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Homework Statement


ABCD is a paralleelogram.angle DAE=angleEAB and angle CBE=angleEBA .Prove that AB=2BC


Homework Equations



none

The Attempt at a Solution


I just got that angle AEB =90 degrees
(But it isn't of any help)
Please help !
 

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Hey I have worked on a solution but i don't know if it's correct.
If i extend the line AE into EF such that FB=BC
and if angle EAB=y=angle FAD and angle CBA=2x
exterior angle FAG=angle FAD+ angleCBA( corresponding angle as CBIIAD)=y+2x
Also, angle FAD=angleFBA +angleAFB
=> 2x+y=angleFBA+2x =>y=angleFBA
.: As angleFAB= angle AFB
.: AB = FB=>
=>AB=2BC
Is it correct? Please let me know if it is wrong.
 

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Last edited:


1/2" said:
Hey I have worked on a solution but i don't know if it's correct.
If i extend the line AE into EF such that FB=BC. FB = FC + BC.
From your second drawing, FB can't possibly be equal to BC. Maybe you didn't say what you meant, but what you said was incorrect.
1/2" said:
and if angle EAB=y=angle FAD and angle CBA=2x
exterior angle FAG=angle FAD+ angleCBA( corresponding angle as CBIIAD)=y+2x
Also, angle FAD=angleFBA +angleAFB
=> 2x+y=angleFBA+2x =>y=angleFBA
.: As angleFAB= angle AFB
.: AB = FB=>
=>AB=2BC
Is it correct? Please let me know if it is wrong.


In your first post you established that angle AEB = 90 deg. You didn't think that was any help, but it is. I worked this problem by labeling all of the interior angles of your original figure.

You are given that DAE = EAB. Let a = the measure of each of these angles. Also, since ABE = EBC, let the measure of each of these angles = b. Since opposite angles of a parallelogram are congruent, ADE = 2b and BCE = 2a.

Now let the measure of DEA = c and the measure of BEC = d. From the fact that the sum of the interior angles of a triangle is 180 deg., you can find c and d, and determine that triangle ADE is isosceles and that triangle BEC is also isosceles. You can also determine that these two triangles are congruent, and once you do that, you can show that AB = 2BC.
 

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