How to Prove the Sine Rule Using Cross Product?

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SUMMARY

The discussion focuses on proving the Sine Rule using the cross product in vector mathematics. It establishes that the area of a triangle can be expressed as A = 1/2 * |a x b| = 1/2 * ab * sin(C), leading to the relationships sin(A)/a = sin(B)/b = sin(C)/c. The proof utilizes the properties of vectors AB, BC, and CA, demonstrating that their sum equals zero and that the cross products yield consistent results. This method effectively confirms the Sine Rule through vector analysis.

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  • Understanding of vector operations, specifically cross products
  • Familiarity with the Sine Rule in trigonometry
  • Basic knowledge of triangle geometry and area calculations
  • Proficiency in manipulating vector equations and identities
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  • Explore geometric interpretations of the Sine Rule
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Could anyone tell me how to use the cross product to prove the sine rule
 
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Area of a triangle of side a.b and c is
A = 1/2*axb = 1/2absinC
Similarly 1/2*bxc = 1/2 bcsinA and so on
So
absinC = bcsinA = casinB. Dividing abc to all we get
sinA/a = sinB/b = sinC/c
 
Here AB,BC,CA ,a,b,c are vectors and AB=a BC=b CA=c
in a triangle ABC,
AB + BC + CA = 0
a + b + c= 0
a x b =b x c = c x a(proved using above statement just take b and c to other side and take crossproduct with b on both sides first and then with c)
la x bl= |b x c|= |c x a |
|a||b| SinC= |b||c|SinA=|a||c| SinB
dividing by |a||b||c|
we get Sine formula
 
Last edited:

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