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How to rearrange this equation for o

Thread starter peter456
Start date Jun 7, 2008
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peter456

Thread starter
Jun 7, 2008

#1

o = theta

how the hell do you rearrange for o?

(1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t

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Astronuc

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Jun 7, 2008

#2

Are both functions tan^2(o/2)?

If so, what is the associative rule when functions are the same, i.e. a f(x) + b f(x) ?

Last edited: Jun 7, 2008

peter456

Jun 8, 2008

#3

Astronuc said:

Are both functions tan^2(o/2)?

If so, what is the associative rule when functions are the same, i.e. a f(x) + b f(x) ?

Sorry i made a mistake, it' really:

(1/6)tan^2(o/2) + (1/2)tan(o/2) = t

HallsofIvy

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Jun 8, 2008

#4

If you let x= tan(o/2) then the equation is (1/6)x²+ (1/2)x= t or, equivalently,
x²+ 3x- 6t= 0. Can you solve that for x (in terms of t)?

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