- #1

- 14

- 0

o = theta

how the hell do you rearrange for o?

(1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t

how the hell do you rearrange for o?

(1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t

- Thread starter peter456
- Start date

- #1

- 14

- 0

o = theta

how the hell do you rearrange for o?

(1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t

how the hell do you rearrange for o?

(1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t

- #2

Astronuc

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Are both functions tan^2(o/2)?

If so, what is the associative rule when functions are the same, i.e. a f(x) + b f(x) ?

If so, what is the associative rule when functions are the same, i.e. a f(x) + b f(x) ?

Last edited:

- #3

- 14

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Sorry i made a mistake, it' really:Are both functions tan^2(o/2)?

If so, what is the associative rule when functions are the same, i.e. a f(x) + b f(x) ?

(1/6)tan^2(o/2) + (1/2)tan(o/2) = t

- #4

HallsofIvy

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