o = theta
how the hell do you rearrange for o?
(1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t
Are both functions tan^2(o/2)?
If so, what is the associative rule when functions are the same, i.e. a f(x) + b f(x) ?
Sorry i made a mistake, it' really:
(1/6)tan^2(o/2) + (1/2)tan(o/2) = t
If you let x= tan(o/2) then the equation is (1/6)x2+ (1/2)x= t or, equivalently,
x2+ 3x- 6t= 0. Can you solve that for x (in terms of t)?
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