1. Jun 7, 2008 #1

   peter456

   

   o = theta
   
   how the hell do you rearrange for o?
   
   (1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t

    

   peter456, Jun 7, 2008
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3. Jun 7, 2008 #2

   Astronuc

   

   Staff: Mentor

   Are both functions tan^2(o/2)?
   
   If so, what is the associative rule when functions are the same, i.e. a f(x) + b f(x) ?

    

   Last edited: Jun 7, 2008

   Astronuc, Jun 7, 2008
4. Jun 8, 2008 #3

   peter456

   

   Sorry i made a mistake, it' really:
   
   (1/6)tan^2(o/2) + (1/2)tan(o/2) = t

    

   peter456, Jun 8, 2008
5. Jun 8, 2008 #4

   HallsofIvy

   

   Staff Emeritus

   Science Advisor

   If you let x= tan(o/2) then the equation is (1/6)x²+ (1/2)x= t or, equivalently,
   x²+ 3x- 6t= 0. Can you solve that for x (in terms of t)?

    

   HallsofIvy, Jun 8, 2008

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