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How to rearrange this equation for o

  1. Jun 7, 2008 #1
    o = theta

    how the hell do you rearrange for o?

    (1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t
  2. jcsd
  3. Jun 7, 2008 #2


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    Are both functions tan^2(o/2)?

    If so, what is the associative rule when functions are the same, i.e. a f(x) + b f(x) ?
    Last edited: Jun 7, 2008
  4. Jun 8, 2008 #3
    Sorry i made a mistake, it' really:

    (1/6)tan^2(o/2) + (1/2)tan(o/2) = t
  5. Jun 8, 2008 #4


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    If you let x= tan(o/2) then the equation is (1/6)x2+ (1/2)x= t or, equivalently,
    x2+ 3x- 6t= 0. Can you solve that for x (in terms of t)?
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