How to rearrange this equation for o

1. Jun 7, 2008

peter456

o = theta

how the hell do you rearrange for o?

(1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t

2. Jun 7, 2008

Staff: Mentor

Are both functions tan^2(o/2)?

If so, what is the associative rule when functions are the same, i.e. a f(x) + b f(x) ?

Last edited: Jun 7, 2008
3. Jun 8, 2008

peter456

Sorry i made a mistake, it' really:

(1/6)tan^2(o/2) + (1/2)tan(o/2) = t

4. Jun 8, 2008

HallsofIvy

Staff Emeritus
If you let x= tan(o/2) then the equation is (1/6)x2+ (1/2)x= t or, equivalently,
x2+ 3x- 6t= 0. Can you solve that for x (in terms of t)?