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o = theta
how the hell do you rearrange for o?
(1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t
how the hell do you rearrange for o?
(1/6)tan^2(o/2) + (1/2)tan^2(o/2) = t
Sorry i made a mistake, it' really:Are both functions tan^2(o/2)?
If so, what is the associative rule when functions are the same, i.e. a f(x) + b f(x) ?