How to Resolve a Vector into Parallel Components?

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Homework Help Overview

The discussion revolves around resolving a position vector into components parallel to specified directions, specifically OB and OC, as illustrated in a provided figure. The subject area includes vector projections and trigonometry.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find the component of vector A parallel to OC by calculating angles in triangle AOC. Some participants discuss the formula for vector projection, questioning the implications of using different vectors for projection.

Discussion Status

Participants are exploring different methods for calculating vector projections and discussing the implications of their approaches. There is no explicit consensus on the correct method or outcome, and some guidance on vector projection formulas has been shared.

Contextual Notes

The original poster mentions a discrepancy between their calculated component and the value provided in a textbook, indicating potential assumptions or interpretations that may need clarification.

blackandyello
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Homework Statement



Resolve the position vector A of the car (measured from fixed point O)
into components parallel to OB and OC.

Figure: http://screensnapr.com/e/4D2OAz.png

Homework Equations



Projection of vector A to OC = |A| * |unit vector OC| * unit vector

The Attempt at a Solution



my solution for finding the component parallel to OC is by finding the angle of triangle AOC, then use that angle to compute for parallel component at OC. my answer ended up to be the same 3500m. but the book says, 2570m along OC.
 
Last edited by a moderator:
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A.B = ABCosθ is the projection of vector A along B.
 
humanist rho said:
A.B = ABCosθ is the projection of vector A along B.

But if you take B = A then you find the projection of A along A is A^2
 
JHamm said:
But if you take B = A then you find the projection of A along A is A^2

oh sorry. I mean B cosθ is the projection of B along A.
 

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