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Introductory Physics Homework Help
How to show the root mean square deviation
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[QUOTE="arcTomato, post: 6206218, member: 662241"] At first, Thank you for reply. Your explanation is so easy to understand. I think I didn't understand the problem correctly. I have to take the length like##Λ_{i,1},Λ_{i,2}...,Λ_{i,n_i}=±λ_i##. so ##\sigma^2 = <\left ( \sum_{j=1}^{n_i}\sum_{i} \Lambda_{ij} \right )^2 > = \sum_{i} \sum_{j=1}^{n_i} < \Lambda_{ij}^2 >=\sum_{i} n_i(±\lambda_{i})^2 ## I think this is almost the answer. Right?? [/QUOTE]
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Introductory Physics Homework Help
How to show the root mean square deviation
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