How to simplify algebraic expression

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SUMMARY

The discussion focuses on the simplification of the algebraic expression \(\frac{1}{(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{1}{2}(\frac{x - 3}{x - 2})^{-\frac{1}{2}} \cdot \frac{1}{(x - 2)^{2}}\). Participants confirm that the steps taken in the simplification process are correct, ultimately leading to the simplified form \(\frac{1}{2(x - 3)(x - 2)}\). The discussion highlights the importance of correctly applying exponent rules and fraction multiplication in algebraic expressions.

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  • Understanding of algebraic expressions and simplification techniques
  • Familiarity with exponent rules, particularly negative and fractional exponents
  • Knowledge of fraction multiplication and simplification
  • Basic skills in manipulating rational expressions
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  • Practice simplifying complex rational expressions
  • Learn about common mistakes in algebraic simplification
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hatelove
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\frac{1}{(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{1}{2}(\frac{x - 3}{x - 2})^{-\frac{1}{2}} \cdot \frac{1}{(x - 2)^{2}}

\frac{1}{(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{1}{2}(\frac{x - 3}{x - 2})^{-\frac{1}{2}} \cdot \frac{1}{(x - 2)^{2}} \\<br /> \frac{1}{(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{1}{2}\frac{1}{(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{1}{(x - 2)^{2}} \\<br /> \frac{1}{(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{\frac{1}{2}}{(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{1}{(x - 2)^{2}} \\<br /> \frac{1}{(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{1}{2(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{1}{(x - 2)^{2}} \\<br /> \frac{1}{(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{1}{(\frac{x - 3}{x - 2})^{\frac{1}{2}}} \cdot \frac{1}{2(x - 2)^{2}} \\<br /> \frac{1}{(\frac{x - 3}{x - 2})} \cdot \frac{1}{2(x - 2)^{2}} \\<br /> \frac{1}{(x - 3)} \cdot \frac{1}{2(x - 2)} \\<br /> \frac{1}{2(x - 3)(x - 2)}

Which step have I done incorrectly?
 
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I don't see that you have done any step incorrectly! What makes you thing you have?
 
Can't find any errors, seems right.
 

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