How to simplify this equation?

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SUMMARY

The equation \(\frac{x+100}{1+\frac{100x}{100^2}}\) simplifies to 100, as confirmed by Wolfram Alpha. The user demonstrated the simplification process by multiplying the equation by \(\frac{100}{100}\) to facilitate factoring. The final steps involved rewriting the equation as \(\frac{100(x+100)}{100+x}\), which clearly shows that the expression simplifies to 100 regardless of the value of x.

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Homework Statement



\frac { x+100 }{ 1+\frac { 100x }{ { 100 }^{ 2 } } }

Homework Equations





The Attempt at a Solution



Wolfram Alpha somehow managed to simplify the equation to just simply 100. Here's my attempt:

\frac { x+100 }{ 1+\frac { 100x }{ { 100 }^{ 2 } } } \\ =\frac { x+100 }{ 1+\frac { 100x }{ { 100 }^{ 2 } } } *\frac { 100 }{ 100 } \\ =\frac { 100x+{ 100 }^{ 2 } }{ 100+x }
 
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tahayassen said:

Homework Statement



\frac { x+100 }{ 1+\frac { 100x }{ { 100 }^{ 2 } } }

Homework Equations





The Attempt at a Solution



Wolfram Alpha somehow managed to simplify the equation to just simply 100. Here's my attempt:

\frac { x+100 }{ 1+\frac { 100x }{ { 100 }^{ 2 } } } \\ =\frac { x+100 }{ 1+\frac { 100x }{ { 100 }^{ 2 } } } *\frac { 100 }{ 100 } \\ =\frac { 100x+{ 100 }^{ 2 } }{ 100+x }

Can you factorize the numerator?? Can you write it as 100+x times some number?
 
micromass said:
Can you factorize the numerator?? Can you write it as 100+x times some number?

Like this?

\frac { x(1+\frac { 100 }{ x } ) }{ 1+\frac { x }{ { 100 } } }

Edit: Never mind. Got it.

\frac { x+100 }{ 1+\frac { x }{ { 100 } } } \\ =\frac { x+100 }{ 1+\frac { x }{ { 100 } } } *\frac { 100 }{ 100 } \\ =\frac { 100(x+{ 100 }) }{ 100+x } \\ =100
 
Last edited:

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