To solve the equation \(\sqrt{x}+\sqrt{x+8}=8\), first rearrange it to \(\sqrt{x+8}=8-\sqrt{x}\). Squaring both sides gives \(x+8=64-16\sqrt{x}+x\), leading to the equation \(16\sqrt{x}=56\). Dividing by 8 simplifies this to \(2\sqrt{x}=7\), resulting in \(\sqrt{x}=\frac{7}{2}\) and \(x=\frac{49}{4}\). Verification shows that this solution satisfies the original equation.