How to solve for the capacitance of an interlocking plates

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To calculate the capacitance of interlocking plates, the formula C=(Eo*A)/d is used, where Eo is the permittivity of vacuum, A is the area of the plates, and d is the separation distance. The separation between the plates is 1.26 mm, and the effective area is 6.1 cm². The user initially assumed the capacitors were in parallel but later realized that each capacitor consists of two plates, leading to a total of eight capacitors in the configuration. After correcting the assumption, the user is seeking further assistance to arrive at the correct capacitance value in picofarads (pF). The discussion emphasizes the importance of accurately interpreting the capacitor arrangement for proper calculations.
mba444
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Homework Statement



A capacitor is constructed of interlocking
plates as shown in the figure (a cross-sectional
view). The separation between adjacent
plates is 1.26 mm, and the effective area of
one of the adjacent plates is 6.1 cm2.

http://images.upload2world.com/get-6-2009-upload2world_com_jdqtdnhw.jpg

The permittivity of a vacuum is 8.85419 × 10−12 C2/N · m2.
Ignoring side effects, calculate the capaci-
tance of this unit. Answer in units of pF.


Homework Equations



C=(Eo*A)/d


The Attempt at a Solution



what i did is that i assumed that the capacitors are parrallel therefore i used this equation by plugging the given values .. but still i keep getting the wrong answer ..

i am looking forward for your help
thanx in advance
 
Last edited by a moderator:
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hey mba444, welcome to PF :)
how many capacitors you assumed that are parrallel?
 
thanx for welcoming

2
 
:bugeye:sure not:-p, you know that each capacitor have two plates separated by the vacuum now look again at the pic, got it?!...
 
Ohhh

thereore 8

thanx a lot :shy:
 

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