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How to solve for the capacitance of an interlocking plates

  1. Jun 19, 2009 #1
    1. The problem statement, all variables and given/known data

    A capacitor is constructed of interlocking
    plates as shown in the figure (a cross-sectional
    view). The separation between adjacent
    plates is 1.26 mm, and the effective area of
    one of the adjacent plates is 6.1 cm2.

    http://images.upload2world.com/get-6-2009-upload2world_com_jdqtdnhw.jpg [Broken]

    The permittivity of a vacuum is 8.85419 × 10−12 C2/N · m2.
    Ignoring side effects, calculate the capaci-
    tance of this unit. Answer in units of pF.


    2. Relevant equations

    C=(Eo*A)/d


    3. The attempt at a solution

    what i did is that i assumed that the capacitors are parrallel therefore i used this equation by plugging the given values .. but still i keep getting the wrong answer ..

    i am looking forward for your help
    thanx in advance
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Jun 19, 2009 #2

    drizzle

    User Avatar
    Gold Member

    hey mba444, welcome to PF :)
    how many capacitors you assumed that are parrallel?
     
  4. Jun 19, 2009 #3
    thanx for welcoming

    2
     
  5. Jun 19, 2009 #4

    drizzle

    User Avatar
    Gold Member

    :bugeye:sure not:tongue:, you know that each capacitor have two plates separated by the vacuum now look again at the pic, got it?!...
     
  6. Jun 19, 2009 #5
    Ohhh

    thereore 8

    thanx alot :shy:
     
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