How to Solve Mechanics Problems Involving Framed Structures

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The discussion revolves around solving mechanics problems related to a trapezoidal billboard attached to an inverted L-shaped frame. Participants emphasize the importance of drawing free-body diagrams to identify forces and moments, particularly at the fixed end support. The conversation highlights the need to calculate shear forces and bending moments, with specific attention to the trapezoidal load distribution. Users are encouraged to show their work and calculations, particularly for the applied loads P1 and P2, to facilitate assistance. The overall focus is on understanding equilibrium and the relationships between forces in the context of framed structures.
  • #91
Ok let's crank it out. P1 is (20)(2.15) = 43 and P2 is (20/2)(2.15) = 21.5, so the vert load is 64.5 N. The moment about the support is 43[(2.15/2) +.1 + 4 sin15] + 21.5[(2.15/3) + .1 + 4 sin15] = 134.9 N-m. Or, if you look at the moment at the support in the free body of the slanted member, it's 64.5(4)(sin15) + 68.1 = 134.9 N-m...checks out OK.
 
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  • #92
Using the bending equations, I have a value of approx 88Pa for the induced stresses.

Am I right in using the the biggest moment in the equation, which is at the ground?
 
  • #93
Sorry, 44.24MPa
 
  • #94
D44 said:
Sorry, 44.24MPa
It's somewhere around there, I didn't calc out the numbers, but yes, max bending stress is Mc/I where M is the max moment (139 Nm) occurring at the support, which controls the overall frame structural design. The I term comes from the properties of the hollow circle, and c is its outside radius.
 
  • #95
Hi, i am having the same trouble with this assignment, mainly drawing the free body diagram of each section. Not sure exactly whether to draw it as a full frame or two separate parts.
thanks
 
  • #96
M3_CSL said:
Hi, i am having the same trouble with this assignment, mainly drawing the free body diagram of each section. Not sure exactly whether to draw it as a full frame or two separate parts.
thanks
First draw it as a full frame to determine reactions at the fixed support at the base. Then break it up into the horizontal piece and slanted piece separately to determine forces and moments in each of those members.
 
  • #97
Thanks, so for the horizontal piece, when your working out the vertical forces, how do you know whether to use the 20Mn or the 40Mn? and does it only have 2 downward forces due to the billboard and one moment force due to the slanted piece?
Thank you
 
  • #98
sorry i ment 20Nm and 40Nm
 
  • #99
M3_CSL said:
Thanks, so for the horizontal piece, when your working out the vertical forces, how do you know whether to use the 20 N/m or 40 N/m [/color]? and does it only have 2 downward forces due to the billboard and one moment force due to the slanted piece?
Thank you
The vertical load is the area of the distributed loading diagram. It's a combimation of a rectangle 20 x 2.15 and a triangle with a long leg of 2.15 and a short leg of 20. Total = 64.5 N. The moment at the right hand side of the horizontal member is the equal and opposite of the moment about that point from the given applied loadings.
 

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