Can anyone help me? I have a question with 3 part answers on my Mechanical Principles assignment. I believe I have answered question part 'a' and 'b' but I have been stuck on question part 'c' for days!! So the question is: Q5. The simply supported beam shown in FIG 4 is 5meters long with a Young’s Modulus of 210GN m-2 The cross section of the beam is as shown in FIG 5 . (a) Draw the shear force diagram for the beam Solution: (b) Determine the position and magnitude of the maximum bending moment. Solution: Giving the moments at 1 meter intervals.. (c) Plot a graph of deflection along the length of the beam (calculate the deflection at 1m intervals). Solution so far.. I understand as it has a U.D.L over a 4 meter spread we can focus the weight at its half way point, 4 * 10 kN = 40kN at 2m(half way) from R1. As there already is a load at 2meters from R1 of 10 meters, This should increase the total load to 50 kN? The Equations I believe are relevant to this are M/I = E/R where: M= bending moment I = The Second Moment of Inetria E = The Youngs Modulus (210GN m-2) R = Radius of curvature of the beam M/EI = d2y/dx2 I = WL3/3EYmax I think I need to work this out using Macauley's method, and it looks difficult. Can anyone advise on nice simple formula to use for each meter interval of deflection?