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Al_Pa_Cone

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Thread moved from the technical forums, so no Homework Help Template is shown.

Can anyone help me? I have a question with 3 part answers on my Mechanical Principles assignment. I believe I have answered question part 'a' and 'b' but I have been stuck on question part 'c' for days!

So the question is:

Q5. The simply supported beam shown in FIG 4 is 5meters long with a Young’s Modulus of 210GN m-2 The cross section of the beam is as shown in FIG 5
.(a) Draw the shear force diagram for the beam

Solution:

(b) Determine the position and magnitude of the maximum bending moment.

Solution:

Giving the moments at 1 meter intervals..

(c) Plot a graph of deflection along the length of the beam (calculate the deflection at 1m intervals).

Solution so far..

I understand as it has a U.D.L over a 4 meter spread we can focus the weight at its half way point,

4 * 10 kN = 40kN at 2m(half way) from R1.

As there already is a load at 2meters from R1 of 10 meters, This should increase the total load to 50 kN?

The Equations I believe are relevant to this are M/I = E/R where:

M= bending moment

I = The Second Moment of Inetria

E = The Youngs Modulus (210GN m-2)

R = Radius of curvature of the beam

M/EI = d2y/dx2

I = WL3/3EYmax

I think I need to work this out using Macauley's method, and it looks difficult. Can anyone advise on nice simple formula to use for each meter interval of deflection?

So the question is:

Q5. The simply supported beam shown in FIG 4 is 5meters long with a Young’s Modulus of 210GN m-2 The cross section of the beam is as shown in FIG 5

Solution:

(b) Determine the position and magnitude of the maximum bending moment.

Solution:

Giving the moments at 1 meter intervals..

(c) Plot a graph of deflection along the length of the beam (calculate the deflection at 1m intervals).

Solution so far..

I understand as it has a U.D.L over a 4 meter spread we can focus the weight at its half way point,

4 * 10 kN = 40kN at 2m(half way) from R1.

As there already is a load at 2meters from R1 of 10 meters, This should increase the total load to 50 kN?

The Equations I believe are relevant to this are M/I = E/R where:

M= bending moment

I = The Second Moment of Inetria

E = The Youngs Modulus (210GN m-2)

R = Radius of curvature of the beam

M/EI = d2y/dx2

I = WL3/3EYmax

I think I need to work this out using Macauley's method, and it looks difficult. Can anyone advise on nice simple formula to use for each meter interval of deflection?