How to Solve Part (b) of the Water Pressure Problem?

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SUMMARY

The discussion focuses on solving part (b) of a water pressure problem involving a tank of water and a pipe. To determine how high the water could shoot from a broken pipe, the Bernoulli equation must be applied at the surface of the tank and at the opening of the pipe. The pressure calculated in part (a) is not applicable for this scenario, as the liquid is in motion, which necessitates a different approach. The key takeaway is that using the static pressure formula, ##\Delta P = \rho g h##, will lead to inaccuracies in this context.

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Homework Statement
A house at the bottom of a hill is fed by a full tank of water 6.0 m deep and connected to the house by a pipe that is 75 m long at an angle of 61° from the horizontal (figure below). (a) Determine the water gauge pressure at the house. (b) How high could the water shoot if it came vertically out of a broken pipe in front of the house?
Relevant Equations
P = pgh
I was able to answer the first portion of the equation

I don't know how to go about answering (b)

here's my work--^
 

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For (b) you'll need to use the Bernoulli equation, applying it at the surface of the tank of water and at the opening of the hole in the pipe.

Note that the pressure you calculated in (a) won't help you here, since ##\Delta P = \rho g h## doesn't apply if the liquid is flowing/not at rest! Using it will make you a factor of ##\sqrt{2}## out...
 
MrInventive said:
Homework Statement:: A house at the bottom of a hill is fed by a full tank of water 6.0 m deep and connected to the house by a pipe that is 75 m long at an angle of 61° from the horizontal (figure below). (a) Determine the water gauge pressure at the house. (b) How high could the water shoot if it came vertically out of a broken pipe in front of the house?
Relevant Equations:: P = pgh

I was able to answer the first portion of the equation

I don't know how to go about answering (b)

here's my work--^
What are your thoughts on (b) so far?
 

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