- #1

vkash

- 318

- 1

**Question**

Number of ordered pair (x,y)(for y not equal to zero) solution of this equation.

**(x+y)+(x/y)=1/2**

**(x+y)(x/y)=-1/2**

options:

(a) 0

(b) 1

(c) 2

(d) none of these {this is my answer}

**My answer**

from second equation (x+y)=(-1/2)(y/x)

putting this in first equation.

(-1/2)(y/x)+(x/y)=1/2

let y/x=t;

-t/2+1/t=1/2

=>t

^{2}+4t-1=0;

Discriminant of this equation is greater than zero so there will two values for y/x;

hence there can be infinite sets of values y,x that can satisfy this equation, so answer should (d) none of these..

But this is not correct where am i doing it wrong.

thanks!

please try to help.