How to Solve Trigonometric Word Problems Correctly?

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SUMMARY

The discussion focuses on solving a trigonometric word problem involving a right triangle with dimensions of 10 feet by 40 feet. The goal is to determine the height from the floor to a beam at a specific point along the 40-foot side, specifically at a height of 16 inches. Participants emphasize the importance of not rounding intermediate values during calculations, as inaccuracies can lead to incorrect results. The correct approach involves using trigonometric functions to find angle measures and heights accurately.

PREREQUISITES
  • Understanding of right triangles and their properties
  • Knowledge of trigonometric functions, specifically sine and cosine
  • Ability to perform calculations with angles in degrees
  • Familiarity with the concept of angle sum in triangles
NEXT STEPS
  • Learn how to apply the sine function in right triangle problems
  • Study the properties of right triangles and angle relationships
  • Explore techniques for solving trigonometric equations without rounding
  • Practice solving real-world trigonometric word problems
USEFUL FOR

Students studying trigonometry, educators teaching geometry, and anyone needing to solve practical trigonometric problems in construction or design.

amd123
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Homework Statement


http://img135.imageshack.us/img135/4150/trighelp.jpg

Homework Equations





The Attempt at a Solution


http://img18.imageshack.us/img18/8480/workz.jpg

Please help I'm totally confused, if anyone can help I can offer a reward of monetary value :).
 
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You are looking for the point along the 40 foot side at which the height from floor to beam is 16 inches. When you find the value, you want to see if it is more than 2 feet away from the righthand side of the wall.
 
Oh thank god, if it works I owe you BUT i don't have any idea how to do that :(
Also are my calculations correct? When i subtract 8.6 from 10 i get 1.4 feet but when i take the sin of 6 degrees * h2 i get 4.2 feet for the height of the beam?
 
Also, since you have a 10 by 40 right-triangle, you should be able to find the measures of the other two angles, and therefore should be able to find the other angle measures in the diagram. Then, you have that lower right-triangle, on the bottom. The angle on the left is easy: the found angle above, the 12 degree, the desired lower angle - their sum is 90 degrees.
 
symbolipoint said:
Also, since you have a 10 by 40 right-triangle, you should be able to find the measures of the other two angles, and therefore should be able to find the other angle measures in the diagram. Then, you have that lower right-triangle, on the bottom. The angle on the left is easy: the found angle above, the 12 degree, the desired lower angle - their sum is 90 degrees.

NVM, didnt read carefully :(
 
amd123 said:
Oh thank god, if it works I owe you BUT i don't have any idea how to do that :(
Also are my calculations correct? When i subtract 8.6 from 10 i get 1.4 feet but when i take the sin of 6 degrees * h2 i get 4.2 feet for the height of the beam?

The numbers you show are close, but not precise. DON'T ROUND INTERMEDIATE VALUES. The height of the small triangle is not 1.4 ft, and the acute angle of the small triangle is not 6 deg. If you use these values, you will probably get the wrong answer. I have no idea how you got 4.2 ft.
 

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