The discussion revolves around solving a trigonometric word problem involving a right triangle with specific dimensions and angles. Participants are attempting to clarify the setup and calculations related to the height of a beam and the distances involved.
The discussion is ongoing, with participants providing guidance on how to approach the problem. There are indications of confusion regarding calculations and angle measures, and some participants are questioning the assumptions made in the problem setup. No consensus has been reached yet.
Participants note potential issues with rounding intermediate values and the need for precise calculations. There is also mention of a reward for assistance, indicating the urgency of the request for help.
symbolipoint said:Also, since you have a 10 by 40 right-triangle, you should be able to find the measures of the other two angles, and therefore should be able to find the other angle measures in the diagram. Then, you have that lower right-triangle, on the bottom. The angle on the left is easy: the found angle above, the 12 degree, the desired lower angle - their sum is 90 degrees.
amd123 said:Oh thank god, if it works I owe you BUT i don't have any idea how to do that :(
Also are my calculations correct? When i subtract 8.6 from 10 i get 1.4 feet but when i take the sin of 6 degrees * h2 i get 4.2 feet for the height of the beam?