How to Solve Vector Calculus Equations Using Lagrange's Formula?

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Discussion Overview

The discussion revolves around solving vector calculus equations using Lagrange's formula. Participants are exploring methods for deriving a specific solution to an equation involving vector operations, including cross products and curls.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • One participant seeks guidance on solving a vector calculus equation and expresses difficulty in deriving the provided solution.
  • Another participant asks whether a general solution is needed or if specific values for the vectors are available, suggesting a sequence of operations involving the cross product and curl function.
  • A third participant mentions the use of Lagrange's formula to transform the expression, providing the formula as a potential method for solving the problem.

Areas of Agreement / Disagreement

There is no consensus on the approach to take, as participants propose different methods and express varying levels of understanding regarding the solution.

Contextual Notes

Participants have not clarified the specific values or conditions for the vectors involved, which may affect the applicability of the proposed methods.

boarie
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Dear all

I'm a newbie here...having some prob and hope to have your expert advice on how to solve the equation attached.

Thx in advance!
 

Attachments

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Do you want a general solution, or have you been given, eg., m=(m1,m2,m3), r=(r1,r2,r3), or have you specific values for the vectors m and r?

Either way, do the cross product first, then divide by the scalar magnitude, then apply the curl function.
 
hi J77

Thx for your reponse.. appreciate your advice...

In fact, the solution to the above is given as attached... I can't seem to derive to the stated form... :cry:

Would really appreciate if any guru can shed some light... :redface:
 

Attachments

  • equation6-27-2006-10.16.32 PM.jpg
    equation6-27-2006-10.16.32 PM.jpg
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Quick reply, but to me the transformation seems to lie in using Lagrange's formula:

[tex]a\times(b\times c)=b(a\cdot c)-c(a\cdot b)[/tex]

ie. "BAC minus CAB"
 

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