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How would I reverse this equation?

  1. Apr 10, 2012 #1
    52x95^0 + 79x95^1 + 0x95^2 + 66x95^3 = 56594307.

    Lets say I'm given 56594307 and 95. How would I find
    out the numbers 52,79,0 and 66?

    Basically if you read the first section of this link
    9.4.1 Text Blocking
    http://www.math.mtu.edu/mathlab/COURSES/holt/dnt/phi4 [Broken].

    I can make a program that can convert from text to
    the block number but I don't know how to go from the
    block number back to text. Sorry if this is something
    really simple that I'm missing.

    Thanks for any help.
    Last edited by a moderator: May 5, 2017
  2. jcsd
  3. Apr 10, 2012 #2
    This is the same as writing the number in a base 95 numeration system.
    So you can use the same procedure used to convert from decimal to binary notation.
    You divide the number by 95 repeatedly until the quotient is less than 95.
    The reminders for each step are the coefficients of the powers of 95 (first reminder is the coefficient of 95^0 and so on).
  4. Apr 11, 2012 #3
    Thanks, it worked.
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