Hybridization of carbanion in rings

Click For Summary
SUMMARY

The discussion centers on the hybridization of carbanions in aromatic compounds, specifically addressing whether a given compound is aromatic, antiaromatic, or nonaromatic. Participants clarify that the carbanion in question is sp2 hybridized due to the presence of a lone pair in a p-orbital, resulting in a total of 8 pi electrons. The conversation emphasizes the importance of resonance structures in determining stability and delocalization of charge around the ring, contrasting valence bond theory with molecular orbital theory.

PREREQUISITES
  • Understanding of hybridization concepts (sp2 and sp3)
  • Familiarity with resonance structures in organic chemistry
  • Knowledge of aromaticity, antiaromaticity, and nonaromaticity
  • Basic principles of valence bond theory and molecular orbital theory
NEXT STEPS
  • Study the concept of resonance structures in depth
  • Learn about molecular orbital theory and its application to aromatic compounds
  • Explore the implications of hybridization on molecular geometry
  • Investigate the relationship between VSEPR theory and valence bond theory
USEFUL FOR

Chemistry students, organic chemists, and anyone interested in understanding the principles of aromaticity and hybridization in organic compounds.

mnmman
Messages
23
Reaction score
0
So this question asked me to determine whether this compound was aromatic, antiaromatic, or nonaromatic and also asked how many pi electrons there were. I figure since there are four groups of electrons the carbanion is sp3 hybridized and I think I'm correct because that is what this thread says.

https://www.physicsforums.com/threads/question-regarding-hybridization-of-carbon.256312/

But apparently the lone pair on this carbanion in this specific compound lies in a p-orbital (as opposed to sp3)? thus making this carbanion sp2 hybridized? for a total of 8 pi electrons. This makes no sense to me any help would be greatly appreciated.
 

Attachments

  • carbanion.jpg
    carbanion.jpg
    8.5 KB · Views: 1,120
Chemistry news on Phys.org
mnmman said:
So this question asked me to determine whether this compound was aromatic, antiaromatic, or nonaromatic and also asked how many pi electrons there were. I figure since there are four groups of electrons the carbanion is sp3 hybridized and I think I'm correct because that is what this thread says.

https://www.physicsforums.com/threads/question-regarding-hybridization-of-carbon.256312/

But apparently the lone pair on this carbanion in this specific compound lies in a p-orbital (as opposed to sp3)? thus making this carbanion sp2 hybridized? for a total of 8 pi electrons. This makes no sense to me any help would be greatly appreciated.

In this particular compound, you can draw resonance structures that move the pair of electrons around the ring. Each of the carbons has one hydrogen bonded to it, and the charge is delocalized around the ring. The only way that this could happen is if each carbon is sp^2.

Remember that Lewis structures are approximations. How about Benzene? The single Lewis structure would predict alternating short and long C-C bonds. The measurement reveals six identical bonds with bond length that is intermediate between C-C and C=C. In the present case, the Lewis structure is incorrect because it predicts a lone pair (with negative charge) on a single carbon -- the lower energy form is with the charge spread out over the entire ring, which is what the resonance structures would predict.
 
Usually this kind of questions is not about hybridization, which is a concept from valence bond theory, as in school aromaticity is introduced using molecular orbital theory. The pi orbitals are formed from p orbitals on the atoms.
 
Quantum Defect said:
draw resonance structures that move the pair of electrons around the ring

ok I can see it now that was very helpful, so if you draw the resonance structures and they end up looking the same but rotated, is that a way you can tell they are especially stable?

DrDu said:
concept from valence bond theory

Does this theory have anything in common with VSEPR? My book only mentions VSEPR and nothing about valence bond theory
 
mnmman said:
Does this theory have anything in common with VSEPR? My book only mentions VSEPR and nothing about valence bond theory
Yes, VSEPR is a scheme that was derived from valence bond ideas, although it is highly simplified.
However terms like hybridization or resonance are from valence bond theory and not VSEPR.
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
10K
Replies
3
Views
7K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 7 ·
Replies
7
Views
40K
Replies
1
Views
14K
  • · Replies 1 ·
Replies
1
Views
4K