Hydraulic motor torque for a home-built flight simulator

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SUMMARY

The discussion centers on determining the necessary torque and specifications for hydraulic motors in a home-built flight simulator capable of lifting 1000 lbs. To achieve a lift of 1 foot in 2 seconds, the motor must provide sufficient torque, RPM, and flow rate. The power required can be calculated using the formula P=Fv, where power equals force multiplied by velocity. Additional factors such as motor efficiency, acceleration, and friction must also be considered for accurate motor selection.

PREREQUISITES
  • Understanding of hydraulic motor specifications and performance metrics
  • Familiarity with torque calculations and power equations
  • Knowledge of hydraulic systems, including flow rates and pressure requirements
  • Basic principles of mechanical advantage using levers
NEXT STEPS
  • Research hydraulic motor torque calculations for lifting applications
  • Learn about hydraulic cylinder alternatives and their advantages
  • Study the impact of motor efficiency on performance in hydraulic systems
  • Investigate flow rate requirements for hydraulic motors in lifting scenarios
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This discussion is beneficial for engineers, hobbyists, and DIY enthusiasts involved in building flight simulators or other projects requiring hydraulic lifting mechanisms.

kenneth roy
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I am constructing a home built flight simulator and am using hydraulic motors with a arm attached to the motor spindle for movement. I need to know how much torque I would need in the motor to lift 1000 lbs. Also I need to know how fast the motor should be to move the weight 1 foot in 2 seconds. Thank you in advance
 
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...using hydraulic motors with a arm attached to the motor spindle for movement. I need to know how much torque I would need in the motor to lift 1000 lbs...

How long is the arm?

Also I need to know how fast the motor should be to move the weight 1 foot in 2 seconds.

Best answer I can give with the info provided is...

1 foot in 2 seconds = 6 inches per second.
 
the arm would be 2'
 
what I wanted to know when I asked about the arm moving, I wished to know how powerful a motor I would need to achieve this. ie: rpm, flow rate etc.
 
You have already defined the motor RPM by setting the time for the 2' arm to travel 6"/s.
The flow rate will depend on the motors swept volume.
You can get a lower limit for power from P=Fv (power =force*velocity). Actual Power required will depend on many other factors - required acceleration, motor efficiency, pipe friction, linkage & bearing friction etc etc.
If you provide a dimensioned sketch we may be able to offer further assistance.
 
sorry I am just a pilot. please elaborate on the acceleration, motor efficiency etc, as I just want someone to tell me what kind of motor I should purchase

thank you again in advance
 
I need to know what size and type of hydraulic motor will lift 1000lbs one foot in one second.

I propose to attach a lever to the motor spindle and attach the end of the lever to the object to be lifted

I need to know the rpm required for the motor, the flow rate in gallons per minute and the psi required to drive the motor to meet these specs

thank you in advance
 
I am no expert in hydraulic machinery, but lifting a heavy load with a lever attached to a motor does not seem a very good idea. Wouldn’t it be more straightforward to use a hydraulic cylinder instead?
 
billy joulebi am currently on holidays and awaymfrom the equipment but will answer you on mymreturn
 

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