Hydraulics and pressure problem

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justduy
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Homework Statement


The hydraulic system is this: It has two stamps (Unsure of how I am to translate that word). Basically it is the plate on which we apply pressure. You apply pressure on one of them, the other goes up. The question is:
How high will the big stamp move upwards when the small one is pressed down with a force F to 6 .0 cm?

Area of the small one = 2.0 cm^2
Radius of the small one = 6 cm

F = 250N

The Attempt at a Solution


The proposed solutions is just answering with this: a (area of the small one) * h (6.0 cm) = AH

ah = AH => H = (ah)/A

I don't understand why?

Thank you in advance.
 
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SteamKing said:
I think for "stamp", the word you are looking for is "piston".

Yep, that's it.
 
justduy said:

Homework Statement


The hydraulic system is this: It has two stamps (Unsure of how I am to translate that word). Basically it is the plate on which we apply pressure. You apply pressure on one of them, the other goes up. The question is:
How high will the big stamp move upwards when the small one is pressed down with a force F to 6 .0 cm?

Area of the small one = 2.0 cm^2
Radius of the small one = 6 cm

F = 250N

The Attempt at a Solution


The proposed solutions is just answering with this: a (area of the small one) * h (6.0 cm) = AH

ah = AH => H = (ah)/A

I don't understand why?

Thank you in advance.
Think about volumes. When one piston is pushed down into the fluid, what volume is displaced? How does that relate to what the other piston does?
 
justduy said:
Area of the small one = 2.0 cm^2
Radius of the small one = 6 cm
I assume you meant to say that the radius of the LARGE piston is 6 cm (not the small one).