Keep working on the liquid pressure problem

In summary, the conversation discusses the calculation of the force of gravity on a piston without taking into account friction. It is determined that the force on each side of the piston must be -ρgSH/2, and the final calculation for the force is F=-(1/2)ρgSH.
  • #1
vxiaoyu18
93
13
Homework Statement
Deep understanding of liquid pressure formula.
Relevant Equations
F=ρgSH
20200101011314-.jpg

Without calculating the friction, if the force of gravity on the piston, the initial force F on the piston S is what?
1. F=-ρgSH;
2. F=-(1/2)ρgSH;
3. F=0;
4. Other.
I'm not sure which is the correct result, can someone help me analyze it again?
 
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  • #2
The force on the left side of the blue piston is ##-\rho g H S_1##. This must also be the force on the right side of the blue piston. So, the pressure inside the compartment must be ##-\rho g H/2## (since the area on the right side of the blue piston is twice the area on the left side of the blue piston). Since S = S1, that means that the force on the left and right sides of the red piston must be ##-\rho gH S/2##.
 
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  • #3
Thank you for your patience. I finally understand. The calculation process of this method is very clear. Is F=-(1/2)ρgSH.
 
  • #4
vxiaoyu18 said:
Thank you for your patience. I finally understand. The calculation process of this method is very clear. Is F=-(1/2)ρgSH.
That's what I said.
 
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