Hydroboration of asymmetric internal alkynes and alkenes?

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Discussion Overview

The discussion centers on predicting the products of asymmetric hydroboration of internal alkynes and alkenes, particularly focusing on the influence of steric hindrance and the nature of the borane used, such as 9-BBN or sterically hindered R2BH. Participants explore the implications of steric factors on product distribution and the resulting structures after oxidation.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants propose that for bulky boranes, the excess product will be the one where the addition of the boryl moiety is least sterically hindered.
  • One participant illustrates this with 2-methyl-2-butene, suggesting that the BR2 moiety will add to the less hindered 3 position, leading to the formation of 3-methyl-2-butanol after oxidation.
  • Another participant questions the steric hindrance in 2-pentene, asking whether the side with more carbons is more hindered and how this applies to 4-methyl-2-pentene.
  • It is noted that the ethyl group in 2-pentene can rotate, which may affect steric hindrance during the reaction.
  • Some participants mention that the placement of bulky groups, like a methyl group, can significantly influence the reaction outcome, while in larger molecules, the effect may be less pronounced.
  • There is a mention of electronic effects in hydroboration, although these are said to be more relevant for groups that can influence electron distribution rather than steric effects.

Areas of Agreement / Disagreement

Participants express varying opinions on the influence of steric hindrance and the effects of different substituents, indicating that multiple competing views remain on how these factors impact product formation. The discussion does not reach a consensus.

Contextual Notes

Participants acknowledge that steric hindrance is a significant factor but also point out that electronic effects may play a role, particularly with electronegative or aryl groups. The discussion remains open regarding the specific contributions of these factors in different scenarios.

fangrz
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How can you predict which product will be in excess if you have asymmetric hydroboration of internal alkynes and alkenes? For example, if I used 9-BBN or something sterically-hindered like R2BH...
 
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For a bulky borane, the excess product will be the one where addition of the boryl moiety is least sterically hindered. (Again, I haven't done these reactions myself, so I'm not a specialist) For example, if you have 2-methyl-2-butene, the 3 position is less sterically hindered than the 2 position. Therefore the BR2 moiety will add to the 3 position and the H (much smaller in size compared to the BR2) will add to the more sterically hindered 2 position. If you're following the hydroboration with a standard oxidation, the major product will ultimately be 3-methyl-2-butanol. Since hydroboration is a syn addition (both substituents add to the same side of the alkene), and the transition state is a 4-membered ring, the addition of the bulky BR2 group to an already sterically crowded position on an alkene is highly energetically unfavorable. This explains the anti-Markovnikov character of the addition.
 
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TeethWhitener said:
For a bulky borane, the excess product will be the one where addition of the boryl moiety is least sterically hindered. (Again, I haven't done these reactions myself, so I'm not a specialist) For example, if you have 2-methyl-2-butene, the 3 position is less sterically hindered than the 2 position. Therefore the BR2 moiety will add to the 3 position and the H (much smaller in size compared to the BR2) will add to the more sterically hindered 2 position. If you're following the hydroboration with a standard oxidation, the major product will ultimately be 3-methyl-2-butanol. Since hydroboration is a syn addition (both substituents add to the same side of the alkene), and the transition state is a 4-membered ring, the addition of the bulky BR2 group to an already sterically crowded position on an alkene is highly energetically unfavorable. This explains the anti-Markovnikov character of the addition.
Thanks! But what if you have, say, 2-pentene? Which side is more sterically-hindered (the one with more carbons?)? And what about if you had 4-methyl-2-pentene? Does the methyl group that's farther away have any effect?
 
fangrz said:
Which side is more sterically-hindered (the one with more carbons?)
My gut says probably. Remember that the ethyl group in 2-pentene can swing 360 degrees around its bond between the 3 and 4 positions, a motion which sweeps out a lot of volume and makes it harder for bulky substituents to attack at the 3 position. Keep in mind, though, that the more similar the groups are, the less difference I'd expect in yield of major vs. minor product. So for something like 3-heptene, where one side has an ethyl group and the other has a propyl group, you probably wouldn't see too much of a difference between major and minor products.

fangrz said:
And what about if you had 4-methyl-2-pentene? Does the methyl group that's farther away have any effect?
The placement of the methyl group in this case ends up making the group pretty bulky, so I imagine the effect would be pretty pronounced here. In (for example) something like 10-methyl-2-dodecene, the extra methyl group probably wouldn't have much of an effect. Also, I should point out that there are electronic effects in hydroboration, but this is more often seen with groups that can push electrons around a little more (electronegative species, aryl groups, etc.). The effects from hydrocarbon groups on stereochemistry tend to be much more easily rationalized in terms of steric considerations.
 
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TeethWhitener said:
My gut says probably. Remember that the ethyl group in 2-pentene can swing 360 degrees around its bond between the 3 and 4 positions, a motion which sweeps out a lot of volume and makes it harder for bulky substituents to attack at the 3 position. Keep in mind, though, that the more similar the groups are, the less difference I'd expect in yield of major vs. minor product. So for something like 3-heptene, where one side has an ethyl group and the other has a propyl group, you probably wouldn't see too much of a difference between major and minor products.The placement of the methyl group in this case ends up making the group pretty bulky, so I imagine the effect would be pretty pronounced here. In (for example) something like 10-methyl-2-dodecene, the extra methyl group probably wouldn't have much of an effect. Also, I should point out that there are electronic effects in hydroboration, but this is more often seen with groups that can push electrons around a little more (electronegative species, aryl groups, etc.). The effects from hydrocarbon groups on stereochemistry tend to be much more easily rationalized in terms of steric considerations.
Thank you!
 

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