Hydrostatic force on submerged curved surface

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The discussion revolves around calculating the hydrostatic force on a submerged curved surface, specifically focusing on the volume calculation needed to determine the weight of the fluid. A user questions the formula presented in their homework solution, which is R^2 - π(R^2)/4, and expresses confusion about its validity as a volume calculation. Other participants clarify that the formula appears to represent an area rather than a volume, suggesting a misunderstanding in the problem statement. The conversation highlights the importance of correctly identifying formulas and their applications in fluid mechanics problems. Accurate comprehension of these calculations is essential for solving related homework effectively.
febbie22
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Homework Statement



Hi i know how to do these problems but its calculating the weight of the fluid, which you have to do to minus it from the vertical force.

But in the solutions to the problem is say that the volume is R^2 - Pie *(R^2)/4 *1

The only thing i want to know is why is that the volume because I've never seen anything like it and if it is correct is it in all the problems so i can just remeber it.


Cheers
 
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Hi febbie22! :smile:

(have a pi: π and try using the X2 tag just above the Reply box :wink:)

Can you give us more detail about this problem?

(and there's no way that R2 - πR2/4 can be a volume … it's obviously an area :confused:)
 
Hi its question 11-19, i triedto put it on word but it didnt let me upload. And I've got the solutions to the problem. and so when it says to calculate the weight it says

rowg * (R^2 - Pie * (R^2)/4 * 1
 

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febbie22 said:
Hi its question 11-19, i triedto put it on word but it didnt let me upload. And I've got the solutions to the problem. and so when it says to calculate the weight it says

rowg * (R^2 - Pie * (R^2)/4 * 1

(please use the X2 tag just above the Reply box :wink:)

I can't find that formula … which page is it on? :confused:

(and it's spelt rho, and you must have missed out an h … that's still an area!)
 
oh sorry it example 11-2 on page 494

and its the weight of fluid block per m length

that i don't get
 
febbie22 said:
oh sorry it example 11-2 on page 494

and its the weight of fluid block per m length

that i don't get

I can't see a page 494 …

have you posted the correct document? :confused:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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