Hydrostatic force on submerged curved surface

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SUMMARY

The discussion centers on calculating the hydrostatic force on a submerged curved surface, specifically addressing the formula for the volume of fluid involved. The formula presented, R² - π(R²)/4, is incorrectly identified as a volume when it is actually an area. Participants clarify that the correct approach involves using the density of the fluid (ρ) and gravitational acceleration (g) to compute the weight of the fluid block per meter length, referencing Example 11-2 on page 494 of a textbook.

PREREQUISITES
  • Understanding of hydrostatic pressure principles
  • Familiarity with fluid mechanics terminology
  • Knowledge of basic calculus for volume and area calculations
  • Experience with reading and interpreting engineering textbooks
NEXT STEPS
  • Review hydrostatic pressure calculations in fluid mechanics
  • Study the derivation of fluid volume formulas in curved surfaces
  • Learn about the application of the density of fluids (ρ) in hydrostatics
  • Examine Example 11-2 in the relevant textbook for practical applications
USEFUL FOR

Students studying fluid mechanics, engineers working with hydrostatic systems, and anyone involved in calculating forces on submerged surfaces will benefit from this discussion.

febbie22
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Homework Statement



Hi i know how to do these problems but its calculating the weight of the fluid, which you have to do to minus it from the vertical force.

But in the solutions to the problem is say that the volume is R^2 - Pie *(R^2)/4 *1

The only thing i want to know is why is that the volume because I've never seen anything like it and if it is correct is it in all the problems so i can just remeber it.


Cheers
 
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Hi febbie22! :smile:

(have a pi: π and try using the X2 tag just above the Reply box :wink:)

Can you give us more detail about this problem?

(and there's no way that R2 - πR2/4 can be a volume … it's obviously an area :confused:)
 
Hi its question 11-19, i triedto put it on word but it didnt let me upload. And I've got the solutions to the problem. and so when it says to calculate the weight it says

rowg * (R^2 - Pie * (R^2)/4 * 1
 

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febbie22 said:
Hi its question 11-19, i triedto put it on word but it didnt let me upload. And I've got the solutions to the problem. and so when it says to calculate the weight it says

rowg * (R^2 - Pie * (R^2)/4 * 1

(please use the X2 tag just above the Reply box :wink:)

I can't find that formula … which page is it on? :confused:

(and it's spelt rho, and you must have missed out an h … that's still an area!)
 
oh sorry it example 11-2 on page 494

and its the weight of fluid block per m length

that i don't get
 
febbie22 said:
oh sorry it example 11-2 on page 494

and its the weight of fluid block per m length

that i don't get

I can't see a page 494 …

have you posted the correct document? :confused:
 

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