Hydrostatics - submerged lamina

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SUMMARY

The discussion focuses on calculating the depth of the center of pressure for a submerged triangular lamina with a height of 3 meters and a base of 2 meters, positioned 1 meter below the water surface. The centroid of the lamina is determined to be 2.5 meters from the surface using the formula c = (2)(3)^3/36. Participants emphasize that the center of pressure will be located below the centroid, indicating the need for further calculations to find the exact depth.

PREREQUISITES
  • Understanding of hydrostatics principles
  • Familiarity with centroid calculations
  • Knowledge of center of pressure concepts
  • Ability to apply relevant equations in fluid mechanics
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  • Study the derivation of the center of pressure formula for submerged surfaces
  • Learn how to calculate the hydrostatic force on submerged shapes
  • Explore the implications of varying shapes on center of pressure depth
  • Review examples of submerged lamina calculations in fluid mechanics textbooks
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Students studying fluid mechanics, engineers involved in hydraulic design, and anyone needing to understand the behavior of submerged surfaces under fluid pressure.

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Homework Statement


Calculate the depth below the water surface of the centre of pressure of the water pressure acting on the submerged triangular lamina, height 3m, base 2m and located at a depth of 1m below the surface.

Homework Equations


not entirely sure

The Attempt at a Solution



I found the centroid location at 2.5m from the surface, c= (2)(3)^3/36.. now i have no clue what to do. any tips?, I now that the center of pressure must be below this point
 
Last edited:
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Some vital information is missing from the problem statement.
 

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