I cannot work out constants a and b --

  • Thread starter Thread starter tosingoodnessamao
  • Start date Start date
  • Tags Tags
    Constants Work
AI Thread Summary
The discussion revolves around solving for constants a and b in the equation v = ay + by^2, given specific velocity values at different distances from a surface. Two equations were established based on the velocities at 1.5 mm and 3.0 mm from the surface, leading to a system of equations with two unknowns. Initially, a mistake was made by incorrectly multiplying b by y instead of y^2. After recognizing this error, the user successfully solved for the unknowns a and b. The conversation emphasizes the importance of correctly setting up equations to find solutions in mathematical problems.
tosingoodnessamao
Messages
3
Reaction score
0
Homework Statement
If the velocity v of the air in a boundary layer having a dynamic viscosity of 18 × 10−6
kg/ms is given in terms of the distance y from the surface by:
v = ay + by^2
where a and b are constants, calculate the surface shear stress if at 1.5 mm from the surface
the velocity is 75 m/s, and at 3.0 mm from the surface it is 105 m/s.

I know that a is the shear strain/rate and i need to times it by the dynamic viscosity but i really cannot work out a and b.

* update - realised that I forgot to square the value for y when multiplying by b.
Relevant Equations
shear stress = (shear strain/rate) x du/dy
75 = (1.5 x 10^-3)a + (1.5 x 10^-3)b
105 = (3 x 10^-3)a + (3 x 10^-3)b
 
Physics news on Phys.org
You are given three things:
(1) v = ay + by^2 where a and b are constants
(2) at 1.5 mm from the surface the velocity is 75 m/s
(3) at 3.0 mm from the surface the velocity is 105 m/s.

From these, you should be able to set up two equations with two unknowns and solve them for a and b. Have you tried that?
 
  • Like
Likes tosingoodnessamao
Two equations with two unknowns. Have you tried solving them?
 
  • Like
Likes tosingoodnessamao
phyzguy said:
You are given three things:
(1) v = ay + by^2 where a and b are constants
(2) at 1.5 mm from the surface the velocity is 75 m/s
(3) at 3.0 mm from the surface the velocity is 105 m/s.

From these, you should be able to set up two equations with two unknowns and solve them for a and b. Have you tried that?
Yes finally found the unnowns a and b because initially I kept multiplying b by y rather than y^2 which was my mistake.
 
Mayhem said:
Two equations with two unknowns. Have you tried solving them?
Yes I have managed to solve them now I recognised my mistake.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top