Net torque about an axis through point A in a massless rod

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Homework Help Overview

The discussion revolves around calculating the net torque about an axis through point A in a massless rod. Participants are examining the components of forces acting on the rod and how these relate to the torque produced about the specified axis.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are exploring the correct application of trigonometric functions (sine and cosine) to determine the components of forces contributing to torque. There is confusion regarding the angles associated with these forces and how they relate to the axis of rotation.

Discussion Status

There is ongoing dialogue about the correct interpretation of angles and components in relation to the forces acting on the rod. Some participants have provided insights into the reasoning behind using sine or cosine for specific forces, while others are still grappling with these concepts. The discussion is productive, with hints and clarifications being shared.

Contextual Notes

Participants are working under the assumption that the rod is massless, which raises questions about the dynamics involved in the problem. There is also mention of potential typographical errors in the textbook regarding the description of the rod's mass.

  • #31
I’m not confused, I thought the reference line represents an arbitrary fixed line (as an x-axis or a polar axis) from which coordinates of a point are computed.
 
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  • #32
paulimerci said:
I’m not confused, I thought the reference line represents an arbitrary fixed line (as an x-axis or a polar axis) from which coordinates of a point are computed.
Sorry, I misunderstood your picture.

BEA3AE8C-7F2F-4B0D-9027-C26087594271.jpeg
 
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  • #33
paulimerci said:
I’m not confused, I thought the reference line represents an arbitrary fixed line (as an x-axis or a polar axis) from which coordinates of a point are computed.
Another way to look at the angle problem is to write the torque equation as ##\tau = \textbf{F} \times \textbf{d}##. The magnitude of the torque will be ##\tau = F d ~ sin( \theta )## where the angle is between and measured counterclockwise. To do this draw a quick sketch and place the tails of d and F at the same point.

-Dan
 
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  • #34
paulimerci said:
I’m not confused, I thought the reference line represents an arbitrary fixed line (as an x-axis or a polar axis) from which coordinates of a

Lnewqban said:
Sorry, I misunderstood your picture.

View attachment 317371
Thank you!
 
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