The discussion centers on calculating the net torque about an axis through point A in a massless rod scenario. The correct formula for net torque is established as Net torque = (30)(sin45)(1.5) - (10)(sin30)(3), resulting in a value of 16.8 Nm, contrary to an initial miscalculation. Key errors identified include the incorrect application of cosine for the 30N force and misunderstanding the orientation of angles in relation to the axis of rotation. The participants emphasize the importance of using the correct trigonometric functions based on the angle's orientation with respect to the reference lines.
PREREQUISITESStudents and educators in physics, particularly those focusing on mechanics and dynamics, as well as anyone involved in solving problems related to torque and force components in engineering contexts.
Sorry, I misunderstood your picture.paulimerci said:
Another way to look at the angle problem is to write the torque equation as ##\tau = \textbf{F} \times \textbf{d}##. The magnitude of the torque will be ##\tau = F d ~ sin( \theta )## where the angle is between and measured counterclockwise. To do this draw a quick sketch and place the tails of d and F at the same point.paulimerci said:
paulimerci said:
Thank you!Lnewqban said: