paulimerci
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I’m not confused, I thought the reference line represents an arbitrary fixed line (as an x-axis or a polar axis) from which coordinates of a point are computed.
Sorry, I misunderstood your picture.paulimerci said:I’m not confused, I thought the reference line represents an arbitrary fixed line (as an x-axis or a polar axis) from which coordinates of a point are computed.
Another way to look at the angle problem is to write the torque equation as ##\tau = \textbf{F} \times \textbf{d}##. The magnitude of the torque will be ##\tau = F d ~ sin( \theta )## where the angle is between and measured counterclockwise. To do this draw a quick sketch and place the tails of d and F at the same point.paulimerci said:I’m not confused, I thought the reference line represents an arbitrary fixed line (as an x-axis or a polar axis) from which coordinates of a point are computed.
paulimerci said:I’m not confused, I thought the reference line represents an arbitrary fixed line (as an x-axis or a polar axis) from which coordinates of a
Thank you!Lnewqban said: