 #1
Variable_X
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 0
 Homework Statement:

A proton is accelerated through a voltage of 248 kV.
a) Calculate the energy of the proton in electron volt and in Joule.
b) Assuming that the mass of the proton remains the same as its rest mass, calculate the speed of the photon.
c)The proton is curved by a magnetic field of 1.5 Telsa. Calculate the radius of the curvature of its path.
 Relevant Equations:
 N/A
a) 248*10^3 eV for 248kV
Calculate the energy in J
K=248*10^3*1.6*10^19
=396.8*10^19 J
b)
K=(1/2)mv^2
v=sqrt(2k/m)
=sqrt((2*396.8*10^19)/1.67*10^27)
=218^10^3 m/s
c)
r=mv/qB
=1.67*10^27*218*10^3/1.6*10^19*1.5*10^4
=15.17 m
r=mv/qB
=1.67*10^27*218*10^3/1.6*10^19*1.5*10^4
=15.17 m
Calculate the energy in J
K=248*10^3*1.6*10^19
=396.8*10^19 J
b)
K=(1/2)mv^2
v=sqrt(2k/m)
=sqrt((2*396.8*10^19)/1.67*10^27)
=218^10^3 m/s
c)
r=mv/qB
=1.67*10^27*218*10^3/1.6*10^19*1.5*10^4
=15.17 m
r=mv/qB
=1.67*10^27*218*10^3/1.6*10^19*1.5*10^4
=15.17 m