I cant solve a simple Acceleration/Deceleration rate of time problem.

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Homework Help Overview

The problem involves a train's acceleration and deceleration rates while traveling between stations that are 7 km apart. The subject area is kinematics, focusing on motion equations and the effects of acceleration and deceleration on travel time.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of kinematics equations to determine travel time, including the effects of acceleration and deceleration. Questions arise regarding the correct interpretation of acceleration values and the calculations needed to find the total time for the journey.

Discussion Status

The discussion is ongoing, with participants exploring various calculations related to the train's motion. Some guidance has been offered regarding the steps to find distances traveled during acceleration and deceleration, but no consensus has been reached on a simpler method or additional formulas that may be needed.

Contextual Notes

Participants are working within the constraints of the problem, including the maximum speed of the train and the specific distances involved. There is an emphasis on using kinematic equations, and some participants express uncertainty about the best approach to take.

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A train with a maximum speed of 105km/h has an acceleration rate of 0.25m/s² and a deceleration rate of 0.7 m/s². Determine the minimum running time between stations 7km apart, if it stops at all stations.


We are using the basic kinematics equations.
S= volt + 1/2aT²
V=Vo +aT
V² = Vo² +2as


My main problem is what would acceleration be considered, I am giving two variables.
.25m/s² and -0.7 m/s².

So far I have S= 7km which I converted to 7000m
V= 105 km/h which I converted to 29.16m/s
But what about acceleration?
 
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first find the distance train travels while it accelerates to max velocity and also distance is travels while decelerating from max velocity to 0 .. rest distance left is traveled at max velocity.

Find corresponding times and add them
 
Ok first I took the kinematics equation V=Vo+at

29.16m/s= 0+(.25m/s²)t

T= 116.6s for the train to accelerate to a full velocity of 29.16m/s
S = 1700M for the train to travel to full acceleration.
So there is a distance of 5300M left to go.

It takes the train 607.3M to go from full velocity to 0.
T= 41.6s

4692.7M to go.

so at full velocity of 29.16m/s
I divide the 4692.7 M by 29.16m/s to get a time of 160s...

Man is there a easier way to do this, like more kinematics formulas that I might need to know?
 
I'm afraid No
 

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