I can't understand this linear equation at all

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Homework Help Overview

The discussion revolves around graphing the linear equation 3x - 6y = 0 and finding its intercepts. Participants are exploring how to derive multiple points for graphing the line.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss substituting values for x and y to find intercepts and additional points on the line. There are attempts to clarify the distinction between standard form and slope-intercept form, as well as the implications of the equation being in standard form.

Discussion Status

The conversation is ongoing with participants providing guidance on how to find additional points for the graph. Some participants question the original poster's methods and suggest alternative approaches to solving for y when substituting values for x.

Contextual Notes

There is confusion regarding the interpretation of the equation and the expectations for graphing multiple points. The original poster expresses difficulty in understanding how to proceed despite having identified the origin as one of the intercepts.

xilc
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Homework Statement


Alright...

3x - 6y = 0, Graph the linear equation, finding it's intercepts.




Homework Equations


I've tried solving it by putting 0 in for x / y, and I've also tried putting -2 in for x / y, so that y = 2 when I move it over, and the system for my college homework tells me it's wrong either way. I simply don't get it.


The Attempt at a Solution


Quite obviously, if I try to solve it, I get 0,0. However, I have no idea how to get any other problem solution at all... If I put 0 in for x or y to simply get one variable, it ends up being y = 0, or x = 0... But it's telling me I have to graph multiple points. How would I do this?
 
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you have the equation of a line going thru the origin 0,0 so now can you see what the slope of the line is?

Also can you see other points that might be on the line say pick x=2 then what is y?...
 
It might help to put the original equation for the line into standard form,

y = ax + b

From this, you are able to determine the slope, a,and the y-intercept, b

You can also generate points and plot the line.
 
SteamKing said:
It might help to put the original equation for the line into standard form,

y = ax + b

From this, you are able to determine the slope, a,and the y-intercept, b

You can also generate points and plot the line.

It's already in standard form, what are you talking about?

y = mx + b is slope intercept...

Ax + By = C is standard form, and it's in standard form already...
 
xilc said:
It's already in standard form, what are you talking about?

y = mx + b is slope intercept...

Ax + By = C is standard form, and it's in standard form already...

Just convert your equation to intercept form. Using that you can graph by just knowing two points. Intercept form is x/a + y/b=1
 
xilc said:

Homework Statement


Alright...

3x - 6y = 0, Graph the linear equation, finding it's intercepts.




Homework Equations


I've tried solving it by putting 0 in for x / y,
So the line goes through the point (0, 0) (and give both x and y intercepts)

and I've also tried putting -2 in for x / y, so that y = 2
When you put -2 for x, you get -6- 6y= 0

when I move it over,
You get 6y= -6. That does NOT give y= 2. Try again.

and the system for my college homework tells me it's wrong either way. I simply don't get it.


The Attempt at a Solution


Quite obviously, if I try to solve it, I get 0,0. However, I have no idea how to get any other problem solution at all... If I put 0 in for x or y to simply get one variable, it ends up being y = 0, or x = 0... But it's telling me I have to graph multiple points. How would I do this?
Well, yes, a line is determined by two points. One of those points is (0, 0). To get another point put in any value of x you like. x= -2 works fine but you have to solve the equation for y correctly!
 

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