# I don't understand how parameters are eliminated

1. Feb 17, 2015

### Eclair_de_XII

1. The problem statement, all variables and given/known data
Eliminate the parameter and identify the graph of the pair of parametric equations. Determine the domain (the set of x-coordinates) and the range (the set of y-coordinates).

x = sin t, y = -3 sin t - 5

2. Relevant equations
y = -3x - 5
Domain: (-∞,∞)
Range: (-∞,∞)

3. The attempt at a solution
I've already solved this equation by substitution but I don't quite understand how the domain and the range are supposed to make sense. The domain of a sine function can't be higher than one or lower than negative one, right? Because sin2x + cos2x = 1, I don't believe that it's possible. Therefore, the domain of x cannot be (-∞,∞), and the domain of y cannot be (-∞,∞). Can someone explain to me how eliminating parameters is supposed to work?

Last edited: Feb 17, 2015
2. Feb 17, 2015

### SteamKing

Staff Emeritus
You have got the domain and the range of a function confused. The domain is typically the set of x-values over which the function is defined.

3. Feb 17, 2015

### Eclair_de_XII

Do you mean that the range of a sin(t) function is [-1,1], and the domain (the angle) is [0,2π)? I still don't understand how this range and domain are eliminated.

Last edited: Feb 17, 2015
4. Feb 17, 2015

### Staff: Mentor

The value of a sine function can be smaller than zero, but you are right that it is bounded.
That makes the given domain for x questionable.

5. Feb 17, 2015

### vela

Staff Emeritus
You have three different functions in this problem: x=f(t), y=g(t), and y=h(x), so when you talk about the domain and range, you need to specify which function you're considering. The problem is asking you to find the domain and range of h.

The domain of h is, as noted in the problem statement, all of the possible values x can take. That set happens to also be the range of f. You seem to have an idea of what this is, but [0,1] isn't correct. You might want to look at a plot of the sine function.

6. Feb 17, 2015

### Eclair_de_XII

It's [-1,1], isn't it? If that's the case, why isn't the range of y [-2,-8]?

7. Feb 17, 2015

### vela

Staff Emeritus
Why do you think it isn't?

8. Feb 17, 2015

### Eclair_de_XII

It's what the online problem said, that's why.

Last edited: Feb 17, 2015
9. Feb 17, 2015

### vela

Staff Emeritus
Sounds like it, or it wants the answer in a different form than the way you entered it.

10. Feb 17, 2015

### Eclair_de_XII

Okay, thanks.

11. Feb 17, 2015

### SammyS

Staff Emeritus
When you use the interval notation, [a, b], b has to be to the right of a on the number line.

The interval, [-2, -8], is improper.

Last edited: Feb 18, 2015
12. Feb 18, 2015

### vela

Staff Emeritus
Good point. I didn't even notice that.