Suppose the Ksp value of AgCl is 2 x 10^-10.(adsbygoogle = window.adsbygoogle || []).push({});

Lets say we have a saturated solution of AgCl, i.e concentration of Ag+ ions = concentration of Cl+ions = (2 x 10^-10)^0.5=1.41 x 10^-5

Ok so what i know is that if we add more Ag+ ions in the solution, precipitation of AgCl would occur since ionic product is greater than Ksp.

So lets say we add Ag+ ions such that the concentration of Ag+ ions is now 2x10^-4 moldm^-3.

Here is the part i dont understand.

The remaining chloride concentration would be 2x10^-10 divided by 2x10^-4 mol = 1x10^-6 moldm^-3. My question is where did the chloride ions go? i know it has precipitated but it doesnt make sense since the concentration of Ag+ ions did not decrease?

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# I dont understand how solubility product (Ksp) work?

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