I don't understand this question could someone clarify?

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Homework Help Overview

The original poster is trying to understand a problem related to the frictional force of air acting on a falling object with a specified mass and acceleration. The context is within Newton's laws of motion.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the meaning of "frictional force of air" and its relation to the forces acting on the falling object. There are questions about how to interpret the given acceleration and the role of gravity in this context. Some participants explore the implications of different forces on the object's acceleration.

Discussion Status

There is an ongoing exploration of the concepts involved, with some participants providing insights into the relationship between gravity and air resistance. Multiple interpretations of the problem are being discussed, and guidance has been offered regarding the forces at play without reaching a definitive conclusion.

Contextual Notes

Participants express confusion over the terminology used in the problem, particularly regarding air friction and air resistance. There is a recognition of the need for clarity in the problem statement.

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Homework Statement


determine the frictional force of air on a body of mass 0.25 kg falling with an acceleration of 9.2 m/s^2


Homework Equations



I don't know?

The Attempt at a Solution



I don't even know what they are asking.. this is on the Newton's laws chapter.. so what is a "frictional force of air"? I'm guessing that it is the opposite vector to the air then? by the 3rd law? so maybe something like W+Airforce = 0.25(9.2) and then you can solve for the airforce and then use the 3rd law to say that the vector in the opposite direction is opposite?

thank you
 
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What would the acceleration of the falling object be if there were no friction?
 
kuruman said:
What would the acceleration of the falling object be if there were no friction?

thank you for the reply. well, we are given the acceleration right? 9.2 m/s^2? am I right in saying that I am supposed to find the opposite "reaction" vector to the force of the thing falling down? thank you!
 
If gravity were the only force acting on the mass, the acceleration would be 9.8 m/s2. The acceleration is not that. How much force opposite to gravity is required to reduce the acceleration to 9.2 m/s2?
 
kuruman said:
If gravity were the only force acting on the mass, the acceleration would be 9.8 m/s2. The acceleration is not that. How much force opposite to gravity is required to reduce the acceleration to 9.2 m/s2?
Ohhh! I see! wow, this is a cool question. so I guess since the falling acceleration is less than gravity (the standard falling acceleration?) then something is acting to slow it down.. that is the "frictional force of air"? but gravity isn't a force, so I have to consider the
weight-F = 0.25(9.2) ?

also, on the side.. if the acceleration were greater than 9.8, that would mean something is acting to make to go faster right? so I would do weight + F = 0.25(faster acceleration)?

thanks :) I used to hate physics but it is starting to look very cool
 
holezch said:
so I guess since the falling acceleration is less than gravity (the standard falling acceleration?) then something is acting to slow it down.. that is the "frictional force of air"? but gravity isn't a force, so I have to consider the
weight-F = 0.25(9.2) ?

That is exactly right.
 
perfect! thank you!
 
Hey there;

well this is a very usual example but you can always think about raindrops when it comes to friction of air;

raindrops falls with a safe velocity, means that they don't harm you when they fall to your head.If there was no "air friction" a raindrop that is falling to the ground from a cloud which has an altitude of 1km let's say, should have a velocity about 507.6 km/hr.Well a raindrop with that velocity will kill you instantly...
 
Cryphonus said:
Well a raindrop with that velocity will kill you instantly...

Not so fast. The speed of the raindrop is 140 m/s. Assuming a radius of 3 mm, the mass of the drop is 1.13x10-4 kg which gives it a momentum of 1.6x10-2 kg*m/s. A 0.040 kg (40 gram) bullet that has the same momentum, will have to be traveling at 1.6x10-2/0.04 = 0.40 m/s which is a slow walking speed. You can certainly stop that bullet without being Superman and therefore you can stop the drop too.
 
  • #10
Imagine a heavy rain then :D, well to be honest i didnt calculated the momentum for a raindrop, but a hail would surely be deadly without air friction. :)
 
  • #11
interesting remarks, thank you... I thought that air friction would actually have something to do with the friction caused by air... what is air resistance then? I wish they would be more clear about what they want :(
 
  • #12
holezch said:
<snip> ...

thanks :) I used to hate physics but it is starting to look very cool

You're one of us now muh-ha-ha-ha-ha!
stirthepot.gif
 
  • #13
holezch said:
I thought that air friction would actually have something to do with the friction caused by air... what is air resistance then?

Air friction is the force caused solely by friction between the object and the air. Air resistance is the total dragging force of the object caused by the air, it includes both the frictional force and the force caused by the object pushing the air out of the way, which is determined by the shape of the object and the speed of the object.
 
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