I have a few problems dealing with work and kinetic energy

Click For Summary

Homework Help Overview

The discussion revolves around problems related to work and kinetic energy in physics, specifically involving objects in motion under the influence of gravity and other forces. The original poster presents three distinct problems involving a thrown ball, a car accelerating up an incline, and a diver entering a pool.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore various approaches to calculating work done by gravity and average forces, with some suggesting the use of kinematic equations and energy principles. Questions arise about how to determine forces when time is not provided, and there is a focus on conceptual understanding of forces acting on objects.

Discussion Status

Some participants have provided guidance on how to approach the problems conceptually, particularly regarding the forces involved. The original poster expresses uncertainty about specific calculations and the application of formulas, indicating an ongoing exploration of the topics without a clear resolution yet.

Contextual Notes

Participants note the lack of certain information, such as time in the first problem, which complicates the calculations. The original poster also mentions feeling lost in setting up the problems, highlighting the challenges faced in understanding the concepts involved.

shabut NAA
Messages
4
Reaction score
0
1. A 0.267 kg ball is thrown straight up from 1.81 m above the ground. Its initial vertical speed is 8.00 m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.

I know that I will probably need to use the PEg=KE formula, but I am very lost as to how to set this problem up and any help would be appreciated.

__
2.A car (m = 600.0 kg) accelerates uniformly from rest up an inclined road which rises uniformly, to a height, h = 33.0 m. Find the average power the engine must deliver to reach a speed of 20.5 m/s at the top of the hill in 18.3 s(NEGLECT frictional losses: air and rolling, ...)

W=KEf-KEi

W=1/2mv^2-1/2mv^2
W=1/2(600)(205)-0
mgh=600(9.8)(33)
W=6150+194040
W=200190/18.3
W=10939.34
I feel like I'm very close to solving this problem but something didn't turn out right..

____

3. A 96.0 kg diver falls from rest into a swimming pool from a height of 3.70 m. It takes 1.54 s for the diver to stop after entering the water. Find the magnitude of the average force exerted on the diver during that time.

I am pretty sure I should start out with PEg=KE but am not sure where to go from there.


Help on any of these problems would be VERY MUCH appreciated! Thanks guys and this seems like a great physics forum.
 
Physics news on Phys.org
1) This problem is relatively easy if you use W=F(d). Find the displacement of the ball using basic kinematics. Remember your signs!

3) There are several ways of doing this problem, but I would recommend that you look at it conceptually i.e gravity exerts a constant force of mg on the diver on his downard path, while after he is in the water... the water exerts a force that brings him from Vo(the velocity at which he enters the water) to Vf(rest) in the time given... Now find the avg force exerted
 
Last edited:
Thanks, I got the 3rd one right now! 1st I don't really understand how I can find the F for W=Fd. I could figure it out if they gave me time but they didn't..so how can I go about finding the F?
 
shabut NAA said:
Thanks, I got the 3rd one right now! 1st I don't really understand how I can find the F for W=Fd. I could figure it out if they gave me time but they didn't..so how can I go about finding the F?

The question asks about the gravitational force. F = the gravitational force =...
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
Replies
6
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K