I have one question regarding Kinetic Energy

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Tarabas
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The question is.
There are two particles, one with charge -q and the other with charge Q, and -q particle rotates around the Q particle at a radius r1. What is the Energy at this point?
The answer is like this: E= KE + U
So now I know that U= -kQq/r1
But according to the answer: KE= kQq/2r1. And I have no idea how they found this KE. Your help would be appreciated. Thanks in advance.
 
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If one charge is revolving around another, then there is a centripetal force acting on the revolving charge. Can you relate this to the attractive force between the charges? How does this relate to the kinetic energy of the revolving charge?
 
PWiz said:
If one charge is revolving around another, then there is a centripetal force acting on the revolving charge. Can you relate this to the attractive force between the charges? How does this relate to the kinetic energy of the revolving charge?
Thnx. I got it. Now I'm laughing how I couldn't figure it out .
 
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