I solving this problem, I have started but I don't know if I got it right

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SUMMARY

The discussion centers on calculating the cost of vanillin detection in an aircraft hangar, where vanillin can be detected at a concentration of 2.0 x 10^-11 g/L. The volume of the hangar is 5.0 x 10^7 ft³, which converts to 1.42 x 10^9 L. The total mass of vanillin required for detection is calculated as 2.84 x 10^-2 g, leading to a cost of approximately $0.064 based on the price of $112 for 50g of vanillin. The calculations emphasize the sensitivity of olfactory detection.

PREREQUISITES
  • Understanding of unit conversions between cubic feet and liters
  • Basic knowledge of concentration calculations in chemistry
  • Familiarity with cost calculations based on mass and price
  • Awareness of the properties and applications of vanillin
NEXT STEPS
  • Research advanced unit conversion techniques for various measurements
  • Learn about the chemical properties and uses of vanillin in food science
  • Explore methods for detecting trace chemicals in the air
  • Investigate the economics of flavoring agents in food production
USEFUL FOR

Chemists, food scientists, and anyone involved in flavoring agent production or detection will benefit from this discussion.

marilu28
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Vanillin (used to flavor foods) can be detected at 2.0 x 10-11 g/L of air. If the current price of 50g of vanillin is $112, determine the cost to supply enough Vanillin so that you would be able to detect it in an aircraft hanger with a volume of 5.0 x 107ft3

What I did was 5.0x107ft3 x28.32L= 1.42x109L, then I did

2.0x10^-11*g/L 1.42 x10^9L= 2.84x10^-2 g, then


2.84x10^-2 g* $112/50g= $6.36 x10^-2 or $.064?? but it does not seem right to me. Thanks for your help
 
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Yup that looks right.
 


Nice problem. I think the point of this, in addition to making you work out how to do unit conversions and so on, is to demonstrate how incredibly sensitive your sense of smell can be.
 

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