The problem involves two objects dropped from a height of 60 m, one with an initial velocity of 20 m/s and the other with 15 m/s. The goal is to determine the distance of the objects when the first one hits the ground, assuming no air resistance.
The discussion is ongoing, with participants exploring different interpretations of the equations and the implications of initial velocities. Some guidance has been offered regarding the use of the quadratic formula and the need to set up equations for both objects.
There is a mention of whether the value of g can be approximated to 10 m/s² for simplification. Participants are also considering the implications of having two different initial velocities leading to two distinct quadratic equations.
Good. So how can you apply this to solve for the time it takes for the 20 m/s object to reach the ground?Purpplehaze said:D= iV * T + a*t^2/2 I think that's the formula to be used.
Purpplehaze said:D= iV * T + a*t^2/2 I think that's the formula to be used.
Purpplehaze said:Would this work? 2(D-iV)/a = t
No.Purpplehaze said:Would this work? 2(D-iV)/a = t
Purpplehaze said:Then how can I isolate t?
Purpplehaze said:60=20t + 4.9t^2
Good. Now you can put it into standard form and solve it using the quadratic formula (or using whatever method you like).Purpplehaze said:60=20t + 4.9t^2
Good!Purpplehaze said:I got 2 as T for the first one.