I with physics webassign dealing with vectors and force with spring.

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Homework Help Overview

The discussion revolves around a physics problem involving vectors and forces, specifically calculating the angle between two vectors and determining the spring constant for a car's deceleration scenario.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore methods for calculating the angle between vectors using the dot product and question the appropriateness of multiplying vectors directly. There is also discussion on the application of kinematic equations for determining the spring constant, with some participants noting potential errors in the original poster's calculations.

Discussion Status

Some participants have provided insights into the calculations, suggesting the use of the dot product for angle determination and questioning the accuracy of the acceleration value used in the spring constant calculation. Multiple interpretations of the problems are being explored, with no explicit consensus reached yet.

Contextual Notes

The original poster appears to be struggling with the application of physics concepts and equations, leading to confusion in their calculations. There is an indication of missing clarity on the relationship between vector operations and physical interpretations.

kp87
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Homework Statement


1) Calculate the angle between the following vectors.
A = 6.1 i + 4.6 j + 6.3 k and B = 8.2 i + 2.3 j - 7.0 k.

2) What should be the spring constant k of a spring designed to bring a 1320 kg car to rest from a speed of 116 km/h so that the occupants undergo a maximum acceleration of 5.0 g?


Homework Equations



v^2=vo^2+2a(x-xo)
F=-kx=ma

The Attempt at a Solution



1) For this one I don't know how to approach this so I found the force by multiplying it (6.1*8.2)i + (4.6*2.3)j+(6.3*-7.0)k = 16.5 N and I think I'm approaching this wrong.

2) I converted the speed 116 km/h = 31 m/s and 5.0g=49.05 m/s^2.
than used v^2=vo^2+2a(x-xo) to find the distance. x=(v^2-vo^2)/2a
x=31^2/(2*49.05)=9.7961. Next, used F=-kx=ma so k=ma/x, which is 1320*49.05/9.7961=6609.36 N/m and I don't know why this isn't working.
 
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1) Would multiplying two vectors necessarily result in a force? This problem can be assigned to any two vectors, regardless of what they represent - i'd suppose that you may have access to a formula in your notes that relates the angle between vectors and the components you have at your disposal. (Well, related to operations you perform on those components: the dot product)

For the second one, the equation involves the square initial and final velocities - you seem to have forgotten to square the 49ms^-2.
 
1) I did 16.5/sqrt((6.1^2+4.6^2+6.3^2)(8.2^2+2.3^2+(-7^2))=712.93
arccos(16.5/712.93)= 83.67 is that right??
2) 49.05 is the acceleration and the final velocity will be 0 so i squared the initial velocity which is 31
 
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