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## Homework Statement

A 75 gram ice cube at 0 degrees Celcius is placed in 825 grams of water at 25 degrees C. What is the final temperature of the mixture?

## Homework Equations

What is the best formula to use in this question?

## The Attempt at a Solution

I have attempted this problem multiple times. The last time I plugged in these variables:(75g)(2.108kJ/kg-k)(T2-0)=(825g)(4.184J/g*degrees C)(T2-25 degrees C)

The answer is supposed to be 16 degrees C. I can't seem to figure this one out. Any help will be greatly appreciated. Am I missing variables?