Calculating Enthalpy Change of Ice Melting in Water

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SUMMARY

The discussion focuses on calculating the total enthalpy change when ice melts in water, specifically addressing the heat absorbed by the ice and the heat lost by the surrounding water. The total enthalpy change is represented by the equation: mice × Cice × ΔTice + mice × ΔHfus° + mice × cwater × ΔTwater = mcal × Cwater × ΔTcal. A correction was made regarding the use of "mice" instead of "nice" in the equation, emphasizing the need for explicit temperature differences to solve for the final temperature of the water.

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  • Knowledge of temperature change calculations (ΔT).
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shredder666
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If I have a piece of ice melting in a water and eventually comes to equilibrium with the water... The the total enthalpy change includes the following right?

Heat absorbed for ice to get to 0 degrees
Heat absorbed for ice to melt to water
Heat absorbed for the melted ice water to come to equilibrium with the water

And the above is equal to the heat lost by the water surroundings... right?

For people that likes math :P
The total enthalpy change can be represented by the following right?

mice× Cice× ΔTice + niceΔHfus°+ mice× cwater× ΔTwater = mcal × Cwater× ΔTcal
 
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shredder666 said:
And the above is equal to the heat lost by the water surroundings... right?
Right.
shredder666 said:
The total enthalpy change can be represented by the following right?

mice× Cice× ΔTice + niceΔHfus°+ mice× cwater× ΔTwater = mcal × Cwater× ΔTcal
Not quite. In the second term on the left side, "nice" should be "mice". Also, you need to write the temperature changes explicitly as differences between two terms. As it stands, the equation cannot be solved for the final temperature of the water, but the idea behind it is correct.
 

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