Ideal circuit with 4 resistances and one emf.

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SUMMARY

The discussion centers on calculating the current and energy dissipation in a circuit with four resistors and a 12.0 V ideal battery. The resistances are R1 = 5.50 Ω and R2 = 18.0 Ω. The current i1 flows in the positive direction to the right, and the energy dissipated by all four resistors over one minute can be determined using the formula P = I²R. The user successfully resolved the problem despite initial confusion regarding equivalent resistance and energy calculations.

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Mike88
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Homework Statement


In the figure below, R1 = 5.50 , R2 = 18.0 and the ideal battery has an emf E= 12.0 V.
(a) What is the size and direction of current i1? (Take right to be positive.)

(b) How much energy is dissipated by all four resistors in 1.00 min?

Homework Equations


I = E/R
resistive dissipation
P=i2R
P=v2/R

The Attempt at a Solution


I am having trouble trying to find the equivalent resistance to find the current i1. I know it should be in the positive direction to the right.

For part b should i just add up the dissapations for the 4 resistors?
 
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What figure? =D
For part b you are correct, P = I2R is the energy dissipated on that resistor, so you'd have to find the corresponding value of the current going through a particular resistor.
 
noumed said:
What figure? =D
For part b you are correct, P = I2R is the energy dissipated on that resistor, so you'd have to find the corresponding value of the current going through a particular resistor.

I forgot to attach it but i figured the problem out anyway.
 

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