Ideal Gas Law: Solving for V with Constant R: Units L or m3?

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Discussion Overview

The discussion centers on the units of volume (V) when using the ideal gas law equation, specifically whether the resultant units should be in liters (L) or cubic meters (m³) when the gas constant R is set to 8.314 J·mol−1·K−1. The context includes considerations of pressure (P) in pascals (Pa) and temperature (T) in kelvins (K).

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant recalls that volume is typically expressed in liters (L) but questions whether it should be in cubic meters (m³) based on the units used in the ideal gas law.
  • Another participant asserts that the correct unit is m³, encouraging trust in the unit analysis.
  • A different viewpoint mentions that using R = 8.314 x 10³ would yield volume in liters, suggesting an alternative unit system with R = 0.0821 L-atm/(K-mol) for liters.
  • One participant elaborates on the unit conversion, explaining that since 1 Pa = 1 N/m² and 1 N = 1 J/m, it follows that 1 Pa = 1 J/m³, leading to the conclusion that volume must be in m³.

Areas of Agreement / Disagreement

Participants express differing views on the appropriate units for volume, with some advocating for liters and others for cubic meters. The discussion remains unresolved regarding which unit is definitively correct.

Contextual Notes

Participants reference specific unit conversions and relationships, but there are no explicit resolutions to the assumptions or dependencies on definitions that may affect the conclusions drawn.

anisotropic
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When using the ideal gas law equation and solving for V, with constant R = 8.314 J·mol−1·K−1, what are the resultant units? L or m3?

I always remember it being in L, but wouldn't it be m3 based purely on the units being put into the equation?

Other units I'm using:

P: Pa (not kPa)
T: K
 
Last edited:
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m3

Trust your units :smile:

For L one uses 8.314x103
 
Borek said:
For L one uses 8.314x103
Alternatively, there's also the other commonly used unit system, seen in R=0.0821 L-atm/(K-mol)
 
anisotropic said:
When using the ideal gas law equation and solving for V, with constant R = 8.314 J·mol−1·K−1, what are the resultant units? L or m3?

I always remember it being in L, but wouldn't it be m3 based purely on the units being put into the equation?

Other units I'm using:

P: Pa (not kPa)
T: K


what you need to know to answer the question is that 1 Pa = 1 N/m^2 (Newton per meter squared) and that 1 N = 1 J/m so that 1 Pa = 1 J/m^3 which shows that V comes out in m^3
 

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