Identical bulbs, rank by brightness

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Homework Help Overview

The discussion revolves around the brightness of identical bulbs connected in a circuit, specifically focusing on their arrangement in series and parallel configurations. Participants explore the implications of these configurations on light intensity and current flow.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the brightness of bulbs A, B, and C, with some asserting that A and C are equally bright while B has no current passing through it. Others question the reasoning behind these conclusions and the implications of an open circuit.

Discussion Status

The conversation is active, with participants expressing agreement and confusion regarding the current flow through bulb B. Some have provided reasoning for their views, while others seek clarification on concepts like open circuits.

Contextual Notes

There is a focus on the definitions and implications of circuit configurations, particularly regarding current flow and the concept of an open circuit. Participants are navigating through assumptions about the connections and their effects on brightness.

kamhogo
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Homework Statement


Which bulb(s) will have the higher light intensity?

Homework Equations


Resistors:
Connection in series: same current
Connection in parallel: same delta V

The Attempt at a Solution


A and C are in series. They'll be equally bright. B is not connected to the negative terminal of the battery. no current will pass through it. Hence A=B>C
 
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kamhogo said:

Homework Statement


Which bulb(s) will have the higher light intensity?

Homework Equations


Resistors:
Connection in series: same current
Connection in parallel: same delta V

The Attempt at a Solution


A and C are in series. They'll be equally bright. B is not connected to the negative terminal of the battery. no current will pass through it. Hence A=B>C
 
I agree with your answer and reasoning.
 
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kamhogo said:
Hence A=B>C
huh ?
 
phinds said:
huh ?
Incorrect??
 
kamhogo said:
Incorrect??
well, what do you mean by it? What it says to me is very literal, A equals B and either both are greater than C or at least B is greater than C. I don't see how you get that from what's going on. Do you mean something else?
 
phinds said:
well, what do you mean by it? What it says to me is very literal, A equals B and either both are greater than C or at least B is greater than C. I don't see how you get that from what's going on. Do you mean something else?
I mean that A and B are equally bright and that both are brighter than C
 
kamhogo said:
I mean that A and B are equally bright and that both are brighter than C
Yes, that's what I thought. Is that really what's happening?
 
phinds said:
Yes, that's what I thought. Is that really what's happening?
Sorry, I was confused. I meant A=C>B. Also, is there any current passing through B at all?
 
  • #10
kamhogo said:
Sorry, I was confused. I meant A=C>B.
Yes, that makes sense.

Also, is there any current passing through B at all?
what do you think?
 
  • #11
phinds said:
Yes, that makes sense.

what do you think?
I think there's no current passing through B at all. My reasoning: why would the electrons go through path with a resistor that does not lead to the negative terminal of the battery when they have the choice to take a resistless (ideally) path that leads to the negative terminal of the battery.
 
  • #12
kamhogo said:
I think there's no current passing through B at all. [/color]

My reasoning: why would the electrons go through path with a resistor that does not lead to the negative terminal of the battery when they have the choice to take a resistless (ideally) path that leads to the negative terminal of the battery.
I don't understand this. Can you explain?
 
  • #13
kamhogo said:
I think there's no current passing through B at all. My reasoning: why would the electrons go through path with a resistor that does not lead to the negative terminal of the battery when they have the choice to take a resistless (ideally) path that leads to the negative terminal of the battery.
Your answer is correct. Have you studied what an "open circuit" is?
 
  • #14
cnh1995 said:
Your answer is correct. Have you studied what an "open circuit" is?
Not yet, but I am curious. I'll look it up. Is it when there is a gap somewhere on the circuit so the current pass? What is it useful for?
 
  • #15
kamhogo said:
Not yet, but I am curious. I'll look it up. Is it when there is a gap somewhere on the circuit so the current pass? What is it useful for?
It is the technical term for a "gap" in the circuit, so current can't flow through it.
A circuit needs to be closed for the flow of current. Here, no current flows through bulb B since there's no closed path.
 
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